Among 100 students, x1 have birthdays in January, x2 have birthdays in February, and so on. If x0 = max(x1, x2, …., x12), then the smallest possible value of x0 is
Explanation:
Given, x0 = max(x1, x2, …., x12)
x0 will be minimum when we distribute students all 100 students as equally among the 12 months as possible.
This can be done in the following way: 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9 (Adding these 12 we will get 100)
∴ x0 = max(8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9).
⇒ Minimum value of x0 = 9
Hence, option (d).
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