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Explanation:

2x + 2-x is of the form y + 1/y
Minimum value the expression can take is 2.
Hence, 2x + 2-x ≥ 2

Now, 2 - (x - 2)2
We know, (x - 2)2 ≥ 0
∴ 2 - (x - 2)2 ≤ 2 (From 2 we are subtracting a non-negative number)
Maximum value this expression can have is 2.

The only possibility is both sides are = 2
LHS = 2x + 2-x = 0
This is possible only when x = 0.

When x = 0, RHS = 2 - (x - 2)2 = 2 - 22 = - 2
Hence, at x = 0, LHS ≠ RHS.
∴ There is no solution possible.
Hence, option (a).

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