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Explanation:

Let the distance between home and office be d kms.

d8-d15=3560=712

⇒ d = 10 kms

If he leaves home at 9:10 a.m. and reaches office at 10 a.m., i.e., time taken = 50 minutes = 5/6 hours

∴ Required speed = 105/6 = 12 kmph.

Hence, option (d).

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