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Explanation:

Given, p3 = q4 = r5 = s6 = k

⇒ p3 = k
⇒ p = k1/3

Similarly,
q = k1/4
r = k1/5
s = k1/6

pqr = k1/3 × k1/4 × k1/5 = k1/3 + 1/4 + 1/5 = k47/60

Now, logs(pqr) = logk1/6 k47/60 = 47/10

Hence, option (a).

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