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Explanation:

Suppose the inlet pipes of type A fill in water at the rate ‘a’ units per minute and the inlet pipes of type B fill in water at the rate ‘b’ units per minute.

Therefore we have the following

30(10a + 45b) = 60(8a + 18b)
∴ 300a + 1350b = 480a + 1080b
∴ 180a = 270b
∴ a = 1.5b

Total capacity of the tank
= 300a + 1350b = 300(1.5b) + 1350b
= 1800b

If 7 inlet pipes of type A and 27 inlet pipes of type B are opened, the volume of water filled in every minute

= 7a + 27b = 7(1.5b) + 27b = 37.5b

Therefore the number of minutes taken to fill the tank

=1800b37.5b=48 minutes

Hence, 48.

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