A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With π = 22/7, the volume, in cubic ft, of the remaining part of the cone is
Explanation:
∆ABE ~ ∆ACD
⇒ ABAC = BECD
AB = 3 ft, AC = 12 ft and CD = 4 ft ⇒ BE = 1 ft
The required volumn of the cone = 13π×42×12 - 13π×12×3 = 13π×(192-3) = 13×227×189 = 198 cubic ft.
Hence, 198.
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