Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is
Explanation:
Let distance between A and P be ‘x’ kms. Therefore, distance between P and B = (3x) kms
Let car 1 reaches point P in ‘t’ minutes. Therefore, car 2 takes (t + 60) minutes to reach P.
Speed of car 1 = x/t and speed of car 2 = 3x/(t + 60)
Hence, x2t = 3xt+60
Solving this, we get
t = 12 minutes.
Hence, 12.
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