Question: For how many digits can the complete list of letters associated with that digit be identified?
Explanation:
is ≡ 35 and as ≡ 56 ⇒ s ≡ 5
∴ a ≡ 6 and i ≡ 3
Letters ‘i’ and ‘d’ are common in words ‘bird’ and ‘india’. Numbers ‘1’ and ‘3’ are common in there codes. We know that i ≡ 3. Therefore, d ≡ 1. Also, br = 34
India ≡ 13366, d ≡ 1 a ≡ 6 and i ≡ 3 ⇒ n = 6
of ≡ 79 means o = 7 or 9
As peacock ≡ 5688999, code for ‘o’ must be ‘9’. Therefore, ‘f ≡ 7’.
national ≡ 13666689, a ≡ 6, i ≡ 3 , o ≡ 9 and n = 6 ⇒ tl ≡ 19
the ≡ 458 and tl ≡ 18 ⇒ t ≡ 8 and hence, l ≡ 1
Consider designated ≡ 1135556678.
As d ≡ 1 a ≡ 6, i ≡ 3, n ≡ 6, s ≡ 5, t ≡ 8; eeg ≡ 557. Therefore, e ≡ 5 and g ≡ 7
Now in peacock ≡ 5688999 we know codes for letters e, a, and o.
Therefore, pcck ≡ 8899 i.e., c = 8 or 9
If c ≡ 8, 9 codes both ‘p’ and ‘k’. As ‘9’ codes two letters and one of them in ‘o’, it can not be code for both ‘p’ and ‘k’. Hence, ‘c’ must be coded as 9. And 8 must be the code for both ‘p’ and ‘k’.
Thus, we have
br = 34 and
1 ≡ d, l
3 ≡ i
5 ≡ s, e
6 ≡ a, n
7 ≡ f, g
8 ≡ t, p, k
9 ≡ o, c
Only for 8 and 9, the complete list of letters associated is identified.
Hence, option (c).