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Explanation:

As per the given information either the entire sequence of scans has to be correct or 3 out of the 5 scans have to be in place. So if we consider TIMRL as the original sequence, each of T, I, M, R and L has to be in the correct sequence which is only possible in 1 way. Now if the sequence of scans is out of place, then at least 2 scans will have to be out of place. Which implies that 3 scans are in place. So 3 out of T, I, M, R and L are in place. Now this is possible in 5C3 or 10 ways. So number of different sequences of scans that are allowed = 1 + 10 = 11 ways.

Answer: 11

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