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Explanation:

Let the weights of Deepak and Poonam be d and p respectively.

(50WII + 50WI)/100 = 45

∴ WII + WI = 90    ...(i)

50WI + d – p = 50WII

50WII – d + p = 50WI

∴ 50(WII – WI) = d – p    ...(ii)

From Statement A, WII – WI = 1    ...(iii)

From (i), (ii) and (iii)

WI and WII can be found. Also, d – p = 50    ...(iv)

However this information does not give us the value of p. Statement A is insufficient to answer the question.

From Statement B,

WI = WII = (SumI + d)/51 = (SumII – d)/49

∴ 49(SumI) + 49d = 51(SumII) – 51d

∴ 100d = 51(50WII) – 49(50WI)

∴ 2d = 51WII – 49WI    ...(v)

This alone cannot help us find the value of p. Statement B is insufficient to answer the question.

Considering both statements together, we have values of WI and WII, which can be substituted in (v) to find d, which can be used to find p using (iv).

Hence, option (c).

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