In a tournament, there are n teams T1 , T2 ....., Tn with n > 5. Each team consists of k players, k > 3. The following pairs of teams have one player in common:
T1 & T2 , T2 & T3 ,......, Tn − 1 & Tn , and Tn & T1.
No other pair of teams has any player in common. How many players are participating in the tournament, considering all the n teams together?
Explanation:
Each team has (k – 2) players to itself and shares 2 players with other two teams.
n pairs of teams have 1 player in common and there are n teams.
Total number of players = n(k – 2) + n = nk – 2n + n = nk – n = n(k – 1)
Hence, option (a).
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