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Explanation:

Let CB = x cm

In a right triangle if DC is the altitude from right vertex, DC2 = AC × BC
∴ 62 = 2 × x
⇒ ​​​​​​​x = 18

⇒ AB = 2 + 18 = 20

∴ Diameter of the semicircle = 20

⇒ Radius of the semicircle = 10

∴ Area = 1/2 × π × 102 = 50π sq. cm.

Hence, option (b).

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