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Explanation:

Let the original length, breadth and height of the room be 3x, 2x and x respectively.

∴ The new length, breadth and height are 6x, x and x/2 respectively.

Area of four walls = (2 × length × height) + (2 × breadth × height)

Original area of four walls = 6x2 + 4x2 = 10x2

New area of four walls = 6x2 + x2 = 7x2

∴ Area of wall decreases by [(10x2  − 7x2)/10x2] × 100 = 30%

Hence, option (e).

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