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Explanation:

Let there be x members in the IOC.

As a member cannot vote if his or her city is in contention, the number of voters in Round 1 (R1) = x – 4

The number of voters in Round 2 (R2) = x – 3 and

The number of voters in Round 3 (R3) = x – 2 – n

Where n is the number of voters who have voted for New York (NY) in R1 and Beijing (B) in R2.

Since x – 3 = 83, we get x – 4 = 82 and x – 2 – n = 75 or n = 9

21 members voted for B in R2. Out of these, 9 voted for NY in R1.

The remaining 12 who voted for B comprised 75% of those who voted for B in R1.

Thus 12/0.75 = 16 members voted for B in R1. 

∴ Paris (P) got 82 – 16 – 30 – 12 = 24 votes in R1. 

All those who voted for London (L) and P in R1 continued to vote for the same cities in subsequent rounds. Thus, 24 voters of P in R2 had voted for P in R1 too. Also from the given information, 3 voters who had voted for NY in R1 voted for Paris in R2.

Out of the remaining 5 that voted for P in R2, 4 had voted for Beijing in R1 and 1 vote came from the member who represented NY. 

In R3, the difference in the votes cast for L and P was 1, i.e. L and P got 37 and 38 votes in some order.

The composition of 75 voters of R3 was as follows:

12 members who had voted for B in R1 and R2 were eligible for voting in R3.

30 and 24 members who voted for L and P in R1 continued to do so in R3.

4 voters of R3, voted for B in R1 and P in R2.

3 voters of R3, voted for NY in R1 and P in R2.

1 member represented NY and 1 represented B. 

From given information, 50% of voters of B in R1 i.e. 8 voted for P in R3. So, 8 out of the 12 who voted for B in R1 and R2, voted for London in R3. 

The information can be summarised as shown in the table:

​​​​​​​

Required percentage = 912 × 100 = 75%

Hence, option (d).

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