If ab+c=bc+a=ca+b=r, then r cannot take any value except _________.
Explanation:
Given, ab+c=bc+a=cc+a=r
By property of equal ratios,
a+b+cb+c+c+a+a+b = r
∴ a+b+c2(a+b+c) = r
Assuming (a + b + c ≠ 0),
∴ r = 12
If a + b + c = 0, a = –(b + c)
Then from the original ratio, r = ab+c = -(b+c)(b+c)= -1
Hence, option (c).
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