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Explanation:

Given, ab+c=bc+a=cc+a=r

By property of equal ratios,

a+b+cb+c+c+a+a+b = r

a+b+c2(a+b+c) = r

Assuming (a + b + c ≠ 0),

∴ r = 12

If a + b + c = 0, a = –(b + c)

Then from the original ratio, r = ab+c = -(b+c)(b+c)= -1

Hence, option (c).

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