If the sum of the first 11 terms of an arithmetic progression equals that of the first 19 terms, then what is the sum of the first 30 terms?
Explanation:
Let a and d be the first term and the common difference of the AP.
Sum of the first n terms of this A.P. = n2[2a + (n - 1)d]
∴ The sum of the first 30 terms = 15 × (2a + 29d) …(i)
By conditions,
112 × (2a + 10d) = 192 × (2a + 18d)
∴ 11a + 55d = 19a + 171d
∴ 8a = –116d
∴ a = - 29d2
From (i),
∴ The sum of the first 30 terms = 15 × (–29d + 29d)
∴ The sum of the first 30 terms = 0
Hence, option (a).
Alternatively,
If the sum of the first p terms of an A.P. is equal to the sum of the first q terms of the A.P. such that p and q are different, then the sum of the first (p + q) terms of the A.P. is zero.
∴ As the sum of the first 11 and the sum of the first 19 terms of the A.P. is equal, the sum of the first (11 + 19) = 30 terms of the A.P. is zero.
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