Davji shop sells samosas in boxes of different sizes. The samosas are priced at Rs. 2 per samosa upto 200 samosas. For every additional 20 samosas, the price of the whole lot goes down by 10 paisa per samosa. What should be the maximum size of the box that would maximize the revenue?
Explanation:
Consider that N extra packets of 20 samosas each are bought.
∴ Total cost, C = (200 + 20N) × (2 – 0.1N)
= 400 − 20N + 40N − 2N2
= 400 + 20N − 2N2
Maxima (C) = 20 − 4N = 0
∴ N = 5
∴ Revenue will be maximum at N = 5
∴ Total number of samosas = 200 + 20(5) = 300
Hence, option (b).
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