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Explanation:

Let the number of Re. 1, Re. 2 and Re. 5 coins be x, y and z respectively.

x + y + z = 300                           ...(i)

x + 2y + 5z = 960                       ...(ii)

2x + y + 5z = 920                       ...(iii)

Adding equation (ii) and equation (iii), we get,

3x + 3y + 10z = 1880                 ...(iv)

Multiply equation (i) by 3, we get,

3x + 3y + 3z = 900                     ...(v)

Subtracting equation (v) from equation (iv), we get,

7z = 980

∴ z = 140

Hence, option (b).

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