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Explanation:

a + c = e              ... (i)

b – d = d

b = 2d                  ... (ii)

e + a = b              ... (iii)

From (ii), we get,

Either b = 4 and d = 2 or b = 10 and d = 5

From (i) and (iii), we get,

2a + c = b            ... (iv)

∴ b = 4 can easily be eliminated because there is no value of b that will satisfy equation (iv).

∴ b = 10 and d = 5

a = 4 or 6 and e = 6 or 4, but c = 2

Using equation (i), we have,

a = 4 and e = 6

Hence, option (b).

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