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Explanation:

Suppose the width of the walkway is x metres.

∴ Area of walkway = 516 = (60 + 2x) × (20 + 2x) – 60 × 20

516 = 1200 + 120x + 40x + 4x2 – 1200

516 = 4x2 + 160x

x2 + 40x – 129 = 0

(x + 43)(x – 3) = 0

x = 3 or x = − 43

∵ Negative value of width is not possible.

∴ x = 3

Hence, option (c).

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