A train X departs from station A at 11.00 a.m. for station B, which is 180 km away. Another train Y departs from station B at 11.00 a.m. for station A. Train X travels at an average speed of 70 km/hr and does not stop anywhere until it arrives at station B. Train Y travels at an average speed of 50 km/hr, but has to stop for 15 minutes at station C, which is 60 km away from station B enroute to station A. Ignoring the lengths of the trains, what is the distance, to the nearest km, from station A to point where the trains cross other?
Explanation:
Let us assume that they meet after t hours.
∴ 70 × t + 50t-14 = 180
120t = 192.5
t=192.5120
∴ The trains should meet at = 192.5120hrs × 70 kmhrs≅ 112 km
Hence, option (a).
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