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Explanation:

First arrange one red and two blue flags in 3 ways. (i.e. BBR, BRB, RBB)

Now there are four positions (say 1, 2, 3, 4) to arrange 3 white flags. Since the flags at the ends are of different colours, two white flags can’t be at positions 1 and 4 simultaneously. Thus, the three flags can be arranged at 1, 2, 3 or 2, 3, 4 in 2 ways.

Thus, the six flags can be arranged in 3 × 2 = 6 ways.

Hence, option (a).

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