The total distance travelled by Y during the journey is approximately
Explanation:
Now, since X and Y reach C at the same time, 100+BC64.875=AC49.5, Hence, you need to take help from options. i.e. If AC = 105, BC2 = AC2 – AB2 = 1052 – 1002 = 1025 or BC = 32 So, 100+BCAC=132105=1.25
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