Please submit your concern

Explanation:

Since ΔBCE is an equilateral triangle, CE = BC = BE.
And since ABCD is a square, BC = CD. Hence, CD = CE.
So in ΔCDE, we have CD = CE. Hence, ∠EDC = ∠CED.
Now ∠BCE = 60° (since equilateral triangle) and ∠BCD = 90° (since square).
Hence, ∠DCE = ∠DCB + ∠BCE = (60 + 90) = 150°.
So in ΔDCE, ∠EDC + ∠CED = 30° (since three angles of a triangle add up to 180°). Hence, we have ∠DEC = ∠EDC = 15°.

Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All