PQRS is a square. SR is a tangent (at point S) to the circle with centre O and TR = OS. Then the ratio of area of the circle to the area of the square is
Explanation:
In the given figure, the area of the circle = pr2. To find out the area of the circle, we need to find out the length of the side of the square. We know, OR = OT + TR = OT + OS = 2r. In right-angled triangle ORS, OR = 2r and OS = r. So SR2 = OR2 – OS2. But SR2 = Area of the square = 4r2 – r2 = 3r2. Hence, the required ratio = π3.
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