Consider the five points comprising of the vertices of a square and the intersection point of its diagonals. How many triangles can be formed using these points?
Explanation:
We can form a triangle with any 3 points which are not collinear. 3 points out of 5 can be chosen in 5C3 = 10 ways. But of these, the three points lying on the two diagonals will be collinear. So 10 – 2 = 8 triangles can be formed.
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