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Explanation:

Let the work done by a worker be x units, w be the total work and n be the number of workers in the group.

Then, w = Work done on the nth day i.e. last day + Work done on the second last day + … + Work done on the first day

⇒ w = x + 2x + ... + nx = n(n+1)x2 ...(i)

When none of the workers is removed, then

w = nx × 2n3=2n2x3 ...(ii)

From equation (i) and (ii), we get

n(n+1)x2=2n2x3

⇒ n = 3.

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