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Explanation:

Let length of the smaller square be x.

From statement I,Length of ABCDEQ = 10x ≥ 60

Therefore, x ≥ 6

From statement II, Area of rectangle OPQR = 42x2 ≤ 1512

⇒ x2 ≤ 36

∴ x ≤ 6

By combining results from statement I and II we have, x = 6

Now, area under the ling GHI-JKL can be found out using x.

Hence, 3.

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