# IIFT 2016 LRDI | Previous Year IIFT Paper

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**Answer the following question based on the information given below.**

Based on the figure given below, the relationship of the terms to the terms to the right of :: is same as that on the left. Find the missing terms.

**1. IIFT 2016 LRDI | LR - Arrangements**

GHF : CDB :: EFD : ?

- A.
ABJ

- B.
CBD

- C.
IJH

- D.
AJB

Answer: Option A

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**Explanation** :

In all four questions here, the analogy is to be based on the figure rather than the numerical relation between the letters.

The first term in both cases (i.e. GHF and CDB) is a triangle in clockwise sequence.

The second term in the first pair is obtained by going anticlockwise from G and selecting the second vertex similar to G (i.e. skip E and select C). Now, CDB is again a triangle in clockwise order. Using this logic, start from E and go anticlockwise. Skip C and select A. Now, the triangle in clockwise order is ABJ.

Hence, option (a).

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**2. IIFT 2016 LRDI | LR - Arrangements**

HNP : PDA :: DLP : ?

- A.
CDP

- B.
PJG

- C.
PHE

- D.
PME

Answer: Option B

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**Explanation** :

The first term in both cases (HNP and DLP) form approximate right triangles in anti-clockwise directions. Hence, their shape is the same.

Considering the shape that PDA forms, the only options that follow this shape are PJG or PHE.

However, observe in the first pair that in HNP and PDA; D is the second vertex on the pentagon after H, going anti-clockwise.

Consider DLP. The second vertex on the pentagon after D, going anti-clockwise, is J.

Hence, the term should be PJ_. Only PJG satisfies this condition.

Hence, option (b).

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**3. IIFT 2016 LRDI | LR - Arrangements**

AKJO : IOHN :: ? : CLBK

- A.
LDME

- B.
EMGH

- C.
EMDL

- D.
CLDM

Answer: Option C

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**Explanation** :

Observe that AKJO and IOHN have the same shape, and I is the next vertex after A, going anti-clockwise.

CLBK is also the same shape. Since the fourth term is known and the third is to be found, the required vertex should be the next vertex, going clockwise i.e. E.

Hence, the required pattern is EMDL.

Hence, option (c).

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**4. IIFT 2016 LRDI | LR - Arrangements**

BPM : GNJ :: ? : AKD

- A.
FPO

- B.
KPD

- C.
HPB

- D.
FPM

Answer: Option A

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**Explanation** :

Observe that the second term in both cases (GNJ and AKD) have the same shape, and A is the second vertex after G, going clockwise.

The second vertex after B, going clockwise, is F. Starting from F, FPO has the same shape as BPM.

Hence, option (a).

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**Read the following information to answer the question that follows.**

In one of the islands of Neverland, people from two tribes exist namely A and B. On the island there is no other tribe except these two. The activities of these tribes are governed by rigid norms and are strictly obeyed for marriages. The norms are:

- The people of one tribe cannot marry any other member of their own tribe though they can marry people from other tribe.
- After being married, each male member ceases to be a member of that tribe in which he was born and becomes the member of the tribe to which his wife belongs.
- The females continue to remain members of the tribe in which they were born even after marriage.
- On birth, the child becomes the member of the mother’s tribe.
- The males become members of the tribe in which they were born when they become divorcee or widower.
- As per norms, nobody can have more than one spouse at a given point of time.

**5. IIFT 2016 LRDI | LR - Blood Relation**

A female in tribe B can have

a. Maternal Grandmother born in tribe A

b. Paternal Grandmother born in tribe A

- A.
Only a can be true

- B.
Only b can be true

- C.
Both a and b are true

- D.
Neither a nor b can be true

Answer: Option B

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**Explanation** :

A female always remains in the same tribe, irrespective of whether she is married, unmarried, divorced or widowed.

Maternal grandmother is the mother’s mother. If the female is in tribe B, her mother as well as maternal grandmother will always be in tribe B.

Hence, a female in tribe B cannot have her maternal grandmother in tribe A.

Hence, statement a cannot be true.

Now, consider a lady (X) born in tribe A. When she marries, she remains in tribe A, and her husband enters tribe A from tribe B. Assume that she has a son (Y).

Y will also be in tribe A.

When Y marries, Y will move to tribe B. Assume that Y has a daughter (Z). Z will be in tribe B, as it is her mother’s tribe.

Thus, a female in tribe B (i.e. Z) can have her paternal grandmother (i.e. X) born in tribe A.

Hence, statement b is true.

Hence, option (b).

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**6. IIFT 2016 LRDI | LR - Blood Relation**

A boy born in tribe B

- A.
Can have his daughter in tribe B

- B.
Can have his daughter in law in tribe A

- C.
Can have uncle from any tribe

- D.
Can have a divorced son in tribe B

Answer: Option C

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**Explanation** :

A boy born in tribe B (say X), can have a son, daughter, son-in-law or daughter-in-law only if he is married. When he marries, he moves to tribe A. Also, his daughter always remains in tribe A (as it is her mother’s tribe).

Hence, a boy born in tribe B cannot have his daughter in tribe B.

Hence, option (a) is eliminated.

The son of X will be in tribe A (till marriage). When he marries, this son and daughter-in-law will be in tribe B. Hence, X cannot have his daughter-in-law in tribe A.

Hence, option (b) is eliminated.

If this married son gets divorced, he moves back to his mother’s tribe i.e. tribe A. Hence, X cannot have a divorced son in tribe B.

Hence, option (d) is eliminated.

Hence, option (c).

**Note:**

You need not check option 3. However, it can be verified as under:

If the boy is born in tribe B, his mother and her brother will also be in tribe B. This uncle will remain in tribe B before marriage and move to tribe A after marriage.

Hence, a boy born in tribe B can have an uncle in any tribe.

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**7. IIFT 2016 LRDI | LR - Blood Relation**

Which of the following marriages are not permissible as per norms

- A.
Any widower marries his wife’s sister

- B.
Any widow marries the former divorced husband of her daughter

- C.
Any girl of the tribe B marries her mother’s brother

- D.
Any widower born in tribe A marries his brother’s widow

Answer: Option C

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**Explanation** :

Since an invalid marriage is to be found, marriages will be possible in three out of four options.

Considering each option.

**Option 1:**

Let X be born in tribe A. When he marries, he moves to tribe B. He moves back to tribe A, on being widowed. Meanwhile, his wife’s sister is still in tribe B. Since he is currently unmarried, it is possible for him to

marry his wife’s sister.

**Option 2:**

A lady and her daughter will be always remain in the same tribe (say A). Her daughter’s husband would originally have been from tribe B, and would have entered tribe A after marriage. He would have gone back to

tribe B after divorce.

Since the female (widowed) and male (divorced) are currently unmarried and in different tribes, they can get married.

**Option 3:**

If the girl is in tribe B, her mother as well as mother’s brother are also in tribe B.

Since two people of the same tribe cannot marry, this marriage is not permissible.

Also, this uncle will be in tribe A only if he is married. The marriage is still not permissible as a person can only have one spouse at a time.

Hence, option (c).

**Note:**

You need not check option 4, but it can be verified that this marriage is possible.

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**Read the following information carefully and answer the questions given below it.**

Six friends Ana, Belle, Cinderella, Diana, Elsa and Ferida are sitting on the ground in a hexagonal shape discussing their trades i.e. cook, hairdresser, washerwoman, tailor, carpenter and plumber. All the sides of the hexagon are of the same length. The seating arrangement is subject to following conditions.

- Ana is not adjacent to the hairdresser or Cinderella
- The tailor is not adjacent to Cinderella or Elsa but adjacent to Ana.
- Hairdresser and Cinderella are adjacent to each other.
- Plumber is in the middle of tailor and Cinderella in a clockwise direction.
- Cook is adjacent to the Carpenter who is adjacent to Belle in an anti-clockwise direction.
- Ferida is a plumber and Elsa is adjacent the cook.
- In a clockwise direction, the washerwoman is followed by the hairdresser

**8. IIFT 2016 LRDI | LR - Arrangements**

Who is at the same distance from Diana as carpenter is from Diana?

- A.
Belle

- B.
Cinderella

- C.
Tailor

- D.
Plumber

Answer: Option B

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**Explanation** :

You can consider the six hexagonal places as 1-6 in clockwise order as shown below.

The washerwoman is followed by the hairdresser in clockwise direction. Hence, let the washerwoman and hairdresser be at places 1 and 2 respectively.

The hairdresser and Cinderella are adjacent to each other. Hence, Cinderella is either the washerwoman or on place 3, as shown below:

The plumber is between the tailor and Cinderella in clockwise direction. Hence, their clockwise order is: tailor-plumber-Cinderella.

Observe that this is not possible in the second figure, as the sequence there is: washerwoman-hairdresser-Cinderella.Hence, the second case is eliminated and **Cinderella = washerwoman**

Hence, to satisfy the tailor-plumber-Cinderella sequence, the tailor and plumber have to be at places 5 and 6 respectively.

Also, **Ferida = plumber. **Thus, the arrangement becomes:

Ana is not adjacent to the hairdresser or Cinderella. Hence, Ana cannot be on seats 3 and 6. Hence, Ana is at 4 or 5.

Since the tailor is adjacent to Ana, Ana cannot be the tailor. Hence, Ana is on seat 4.

From the above figure, seat 3 and Ana should be cook and carpenter (in no specific order).

However, it is known that in anti-clockwise order, the sequence is cook-carpenter-Belle.

This is only possible if **Ana = cook and Belle = hairdresser.**

Now, Elsa can be the tailor or carpenter, as Elsa is adjacent the cook. Since the tailor is not adjacent to Elsa, Elsa is not the tailor. Hence, **Elsa = carpenter **and **Diana = tailor.**

Thus, the final arrangement is:

From the above figure, the carpenter is two places away from Diana. The other person who is two places away from Diana is Cinderella (the washerwoman).

Hence, option (b).

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**9. IIFT 2016 LRDI | LR - Arrangements**

If one neighbour of cook is Elsa, who is the other?

- A.
Cinderella

- B.
Diana

- C.
Belle

- D.
Ferida

Answer: Option B

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**Explanation** :

You can consider the six hexagonal places as 1-6 in clockwise order as shown below.

The washerwoman is followed by the hairdresser in clockwise direction. Hence, let the washerwoman and hairdresser be at places 1 and 2 respectively.

The hairdresser and Cinderella are adjacent to each other. Hence, Cinderella is either the washerwoman or on place 3, as shown below:

The plumber is between the tailor and Cinderella in clockwise direction. Hence, their clockwise order is: tailor-plumber-Cinderella.

Observe that this is not possible in the second figure, as the sequence there is: washerwoman-hairdresser-Cinderella.Hence, the second case is eliminated and **Cinderella = washerwoman**

Hence, to satisfy the tailor-plumber-Cinderella sequence, the tailor and plumber have to be at places 5 and 6 respectively.

Also, **Ferida = plumber. **Thus, the arrangement becomes:

Ana is not adjacent to the hairdresser or Cinderella. Hence, Ana cannot be on seats 3 and 6. Hence, Ana is at 4 or 5.

Since the tailor is adjacent to Ana, Ana cannot be the tailor. Hence, Ana is on seat 4.

From the above figure, seat 3 and Ana should be cook and carpenter (in no specific order).

However, it is known that in anti-clockwise order, the sequence is cook-carpenter-Belle.

This is only possible if **Ana = cook and Belle = hairdresser.**

Now, Elsa can be the tailor or carpenter, as Elsa is adjacent the cook. Since the tailor is not adjacent to Elsa, Elsa is not the tailor. Hence, **Elsa = carpenter **and **Diana = tailor.**

Thus, the final arrangement is:

Ana is the cook, and her neighbours are Elsa and Diana.

Hence, option (b).

Workspace:

**10. IIFT 2016 LRDI | LR - Arrangements**

What are the trades of Diana and Elsa?

- A.
Tailor and Carpenter

- B.
Cook and Carpenter

- C.
Tailor and Washerwoman

- D.
Tailor and Plumber

Answer: Option A

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**Explanation** :

You can consider the six hexagonal places as 1-6 in clockwise order as shown below.

The washerwoman is followed by the hairdresser in clockwise direction. Hence, let the washerwoman and hairdresser be at places 1 and 2 respectively.

The hairdresser and Cinderella are adjacent to each other. Hence, Cinderella is either the washerwoman or on place 3, as shown below:

The plumber is between the tailor and Cinderella in clockwise direction. Hence, their clockwise order is: tailor-plumber-Cinderella.

Observe that this is not possible in the second figure, as the sequence there is: washerwoman-hairdresser-Cinderella.Hence, the second case is eliminated and **Cinderella = washerwoman**

Hence, to satisfy the tailor-plumber-Cinderella sequence, the tailor and plumber have to be at places 5 and 6 respectively.

Also, **Ferida = plumber. **Thus, the arrangement becomes:

Ana is not adjacent to the hairdresser or Cinderella. Hence, Ana cannot be on seats 3 and 6. Hence, Ana is at 4 or 5.

Since the tailor is adjacent to Ana, Ana cannot be the tailor. Hence, Ana is on seat 4.

From the above figure, seat 3 and Ana should be cook and carpenter (in no specific order).

However, it is known that in anti-clockwise order, the sequence is cook-carpenter-Belle.

This is only possible if **Ana = cook and Belle = hairdresser.**

Now, Elsa can be the tailor or carpenter, as Elsa is adjacent the cook. Since the tailor is not adjacent to Elsa, Elsa is not the tailor. Hence, **Elsa = carpenter **and **Diana = tailor.**

Thus, the final arrangement is:

Diana and Elsa are the tailor and carpenter respectively.

Hence, option (a).

Workspace:

**11. IIFT 2016 LRDI | LR - Arrangements**

Who is sitting opposite to the plumber?

- A.
Ana

- B.
Elsa

- C.
Diana

- D.
Cinderella

Answer: Option B

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**Explanation** :

You can consider the six hexagonal places as 1-6 in clockwise order as shown below.

**Cinderella = washerwoman**

Also, **Ferida = plumber. **Thus, the arrangement becomes:

Since the tailor is adjacent to Ana, Ana cannot be the tailor. Hence, Ana is on seat 4.

From the above figure, seat 3 and Ana should be cook and carpenter (in no specific order).

However, it is known that in anti-clockwise order, the sequence is cook-carpenter-Belle.

This is only possible if **Ana = cook and Belle = hairdresser.**

**Elsa = carpenter **and **Diana = tailor.**

Thus, the final arrangement is:

Ferida is the plumber and Elsa is opposite Ferida.

Hence, option (b).

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**Read the following information carefully to answer the questions given below it.**

A, B, C, E, F, G and H are 7 employees in an organisation working in different departments of Administration, Finance and Logistics. There are at least two employees in each department. Out of these 7, 3 are females and one is in each department. Each employee gets a different salary. F works in Administration and his only other colleague G earns the maximum. C, the least earner works in Finance. B and E are brothers and are not in the same department. A, husband of H, works in Finance and earns more than F, B and E. The wife in the couple earns more than the husband.

**12. IIFT 2016 LRDI | LR - Selection & Distribution**

In which of the department, does a group of 3 work?

- A.
Logistics

- B.
Logistics or Administration

- C.
Administration or Finance

- D.
Finance or Logistics

Answer: Option D

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**Explanation** :

There are seven people in three different departments, such that there are atleast two people per department. Hence, the department-level breakup of people is (3, 2, 2) in any order.

There are three females such that there is one female in each department. Hence, the male-female breakup per department is: (f + m), (f + m), (f + 2m).

F is in Administration and his only colleague is G.

Hence, F = Administration = Male

Also, there are only two people in Administration i.e. F and G, one of whom has to be female.

Hence, G = Administration = Female C = Finance

A is the husband of H and works in Finance. Hence, A = Finance = Male

Since B and E are brothers, both are male and both work in different departments.

Hence, B/E = Finance = Male

Hence, the third person in Finance i.e. C, has to be female. Hence, C = Finance= Female

Since there have to be atleast two people in each department, the two remaining people have to be in Logistics i.e. E/B = Logistics = Male and H = Logistics = Female

Thus, a group of 3 works in Finance.

Hence, option (d).

**Note:**

The correct answer is not given in any of the options. Hence, you can mark the closest possible answer i.e. option 4.

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**13. IIFT 2016 LRDI | LR - Selection & Distribution**

Which of the following statement is true?

- A.
B earns less than A and H

- B.
B earns less than F and H

- C.
F earns more than B and E

- D.
B earns more than E and C

Answer: Option A

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**Explanation** :

Rank the people as 1-7 in descending order of salary i.e. 1 = highest and 7 = lowest

G = 1; C = 7; A > F, B, E

A-H is the couple where H is the wife. Since the wife earns more than the husband, H > A.

Hence, the overall descending order is: G > H > A > (F, B, E) > C.

Hence, B definitely earns less than A and H.

Hence, option (a).

**Note:**

The statements in the remaining options may or may not be true.

Workspace:

**14. IIFT 2016 LRDI | LR - Selection & Distribution**

In descending order of income, H is at which position?

- A.
2

- B.
3

- C.
5

- D.
1

Answer: Option A

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**Explanation** :

Rank the people as 1-7 in descending order of salary i.e. 1 = highest and 7 = lowest

G = 1; C = 7; A > F, B, E

A-H is the couple where H is the wife. Since the wife earns more than the husband, H > A.

Hence, the overall descending order is: G > H > A > (F, B, E) > C.

H is ranked second in descending order of income.

Hence, option (a).

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**15. IIFT 2016 LRDI | LR - Venn Diagram**

The diagram below, explains which of the given relationship

- A.
Judge, Thief, Criminal

- B.
Tea, Coffee, Beverages

- C.
Males, Fathers, Doctors

- D.
Cabinet, Minister, Home Minister

Answer: Option C

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**Explanation** :

Every father is a male, but every male need not be a father. Hence, the set of fathers is the subset of the set of males.

Some males are doctors and some fathers are doctors, and vice versa. Hence, the set of doctors partially intersects the set of males as well as fathers.

Hence, the given diagram corresponds to Males, Fathers, Doctors.

Hence, option (c).

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**16. IIFT 2016 LRDI | LR - Series**

Insert the missing number

- A.
35

- B.
48

- C.
72

- D.
120

Answer: Option B

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**Explanation** :

Middle number = (difference between numbers of left column) × (sum of numbers of right column)

i.e. 80 = (15 – 5) × (2 + 6) = (10) × (8) and 65 = (9 – 4) × (7 + 6) = (5) × (13)

∴ ? = (13 – 11) × (16 + 8) = 2 × 24 = 48

Hence, option (b).

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**17. IIFT 2016 LRDI | LR - Series**

In the following question, one term in the number series is wrong. Find out the wrong term.

10, 26, 74, 218, 654, 1946, 5834

- A.
654

- B.
26

- C.
1946

- D.
218

Answer: Option A

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**Explanation** :

The logic is: given term = (previous term) × 3 – 4

This pattern is broken for 654 i.e.(218 × 3) – 4 = 650

Hence, the wrong term is 654.

Hence, option (a).

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**18. IIFT 2016 LRDI | LR - Coding Decoding**

In the question below, three incomplete rows of letters/numerals are given which correspond to each other in some way. Find the letters/numerals which come in the vacant places marked by “?”

- A.
a, c, d, d

- B.
d, a, c, c

- C.
c, a, d, d

- D.
d, c, a, a

Answer: Option D

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**Explanation** :

The first row has uppercase letters, the second has digits and the third has lowercase letters.

Use terms common to rows to identify the relation between these three groups.

From first two rows: C = 1; and from last two rows: 1 = a i.e. C = 1 = a

Hence, the required term i.e. BDCC corresponds to _ _ aa.

Hence, option (d).

Note: It can be verified that B = 2 = d and D = 4 = c (as A = 3)

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**19. IIFT 2016 LRDI | LR - Syllogisms**

Choose the conclusion which logically follow from the given statement irrespective of commonly known facts.

**Statement:**

All branches are flowers.

All flowers are leaves**Conclusion :**

I. All branches are leaves

II. All leaves are branches

III. All flowers are branches

IV. Some leaves are branches

- A.
None follows

- B.
Only I and IV follow

- C.
Only II and III follow

- D.
All follow

Answer: Option B

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**Explanation** :

Since all branches are flowers, and all flowers are leaves, it implies that all branches are leaves and some leaves are branches.

Hence, conclusions I and IV follow.

Hence, option (b).

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**Read the following information carefully to answer the questions given below it.**

Eight doctors P, Q, R, S, T, U, V and W of the same family i.e. father, mother, father’s sister, mother’s brother, 2 daughters and 2 sons visit a clinic every day for one hour each except on Monday which is a holiday. The timings are 9 am to 1 pm and 2 pm to 6 pm, with lunch time from 1 pm to 2 pm. Each has a different specialisation namely Cardiologist, Orthodontist, Neurologist, Paediatrician, Gynaecologist, Urologist, Radiologist and General Physician.

- No doctor visits the clinic before doctor Q and after doctor U.
- The Orthodontist visits right after lunch and is followed by R who is a female.
- The mother comes in at the same place before lunch as the younger son P after lunch.
- The General Physician is the sister of Urologist’s father and is last to visit before lunch.
- The Cardiologist is the first while the elder daughter is the last to visit.
- T is the mother’s brother of U and visits between the father and mother.
- Before 1 pm, V comes after the Radiologist, who is second to visit during the day
- S, the mother comes at 11 am after the father.
- The Neurologist is at the same place after lunch as the Gynaecologist before lunch and comes right after Urologist.

**20. IIFT 2016 LRDI | LR - Blood Relation | LR - Arrangements**

he General Physician is a ____________ and comes at ___________

- A.
Female, 11am

- B.
Female, 12 noon

- C.
Male, 11am

- D.
Male, 12 noon

Answer: Option B

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**Explanation** :

There are four males: father, mother’s brother and two sons. Similarly, there are four females: mother, father’s sister and two daughters.

Some of the data is directly given and can be tabulated as under:

The following points can be concluded from the table:

- V is the General Physician (as V comes before 1 p.m., but after the radiologist).
- The mother is the Gynaecologist (as the gynaecologist comes before lunch).
- R is the younger daughter.

The following points can now be added:

- Neurologist comes third after lunch (as Gynaecologist comes third before lunch) and Urologist comes second after lunch (as Neurologist is immediately after Urologist). Hence, R is the Urologist.
- Younger son, P, comes third after lunch (as mother comes third before lunch). Hence, P is the Neurologist.
- T (mother’s brother) comes between father and mother, while the father comes before the mother. Hence, Q is the father and T is the Radiologist.

Hence, the only person left i.e. W is the elder son and is the Orthodontist. U is the Paediatrician. The final combinations are as shown below:

Thus, the General Physician is a female and comes at 12 noon.

Hence, option (b).

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**21. IIFT 2016 LRDI | LR - Blood Relation | LR - Arrangements**

R is a _________ by specialization and is Cardiologist’s __________

- A.
Orthodontist, Sister

- B.
Paediatrician, Daughter

- C.
Urologist, Mother

- D.
Urologist, Daughter

Answer: Option D

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**Explanation** :

There are four males: father, mother’s brother and two sons. Similarly, there are four females: mother, father’s sister and two daughters.

Some of the data is directly given and can be tabulated as under:

The following points can be concluded from the table:

- V is the General Physician (as V comes before 1 p.m., but after the radiologist).
- The mother is the Gynaecologist (as the gynaecologist comes before lunch).
- R is the younger daughter.

The following points can now be added:

- Neurologist comes third after lunch (as Gynaecologist comes third before lunch) and Urologist comes second after lunch (as Neurologist is immediately after Urologist). Hence, R is the Urologist.
- Younger son, P, comes third after lunch (as mother comes third before lunch). Hence, P is the Neurologist.
- T (mother’s brother) comes between father and mother, while the father comes before the mother. Hence, Q is the father and T is the Radiologist.

Hence, the only person left i.e. W is the elder son and is the Orthodontist. U is the Paediatrician. The final combinations are as shown below:

R is a Urologist and is the daughter of Q (the Cardiologist).

Hence, option (d)

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**22. IIFT 2016 LRDI | LR - Blood Relation | LR - Arrangements**

If lunch break and subsequent working hours are reduced by 15 minutes on Wednesday, then Doctor U who is _________ and Cardiologist’s __________ will reach the clinic at _______

- A.
Radiologist, Sister, 3:15 pm

- B.
Urologist, Daughter, 4:15 pm

- C.
Paediatrician, Daughter 5:45 pm

- D.
Paediatrician, Daughter, 4:15 pm

Answer: Option D

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**Explanation** :

There are four males: father, mother’s brother and two sons. Similarly, there are four females: mother, father’s sister and two daughters.

Some of the data is directly given and can be tabulated as under:

The following points can be concluded from the table:

- V is the General Physician (as V comes before 1 p.m., but after the radiologist).
- The mother is the Gynaecologist (as the gynaecologist comes before lunch).
- R is the younger daughter.

The following points can now be added:

- Neurologist comes third after lunch (as Gynaecologist comes third before lunch) and Urologist comes second after lunch (as Neurologist is immediately after Urologist). Hence, R is the Urologist.
- Younger son, P, comes third after lunch (as mother comes third before lunch). Hence, P is the Neurologist.
- T (mother’s brother) comes between father and mother, while the father comes before the mother. Hence, Q is the father and T is the Radiologist.

Hence, the only person left i.e. W is the elder son and is the Orthodontist. U is the Paediatrician. The final combinations are as shown below:

U is a Paediatrician and is the daughter of the Cardiologist.

Hence, options 1 and 2 can be eliminated.

Originally, she used to reach at 5 p.m. Now she will reach before 5 p.m.

Hence, option (d).

**Note:**

U will actually reach at 4 p.m. and not 4:15 p.m. Hence, none of the answers is actually correct.

Workspace:

**Answer the following question based on the information given below.**

After receiving the disturbing news of falling standards the Supreme Council of Confederation of five Kingdoms is considering to conduct joint entrance examination for all student in these kingdoms for Vaidya Ratna course. As a first step, it has been decided to review the past five years data about the individual entrance examination of the kingdoms so that an appropriate action can be taken. Study the table given below and answer the questions.

**23. IIFT 2016 LRDI | DI - Tables & Graphs**

What is the overall pass percentage from Anga Kingdom for all the years together?

- A.
16.7

- B.
17.5

- C.
18.7

- D.
15.5

Answer: Option A

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**Explanation** :

Total appeared for Anga

= 5000 + 5500 + 6000 + 5000 + 7000

= 28500

Total passed from Anga

= 850 + 770 + 1200 + 750 + 1190

= 4760

∴ Required % = (4760/28500) × 100

= 16.7%

Hence, option (a).

Workspace:

**24. IIFT 2016 LRDI | DI - Tables & Graphs**

In which of the following years, total number of candidates passed from all the kingdoms is lowest?

- A.
2012

- B.
2013

- C.
2014

- D.
2015

Answer: Option D

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**Explanation** :

Consider the total number of candidates passed from all kingdoms in each year in the options.

2012: 850 + 640 + 468 + 780 + 765 = 3503

2013: 770 + 810 + 275 + 1120 + 595 = 3570

2014: 1200 + 1235 + 266 + 715 + 810 = 4226

2015: 750 + 880 + 275 + 935 + 520 = 3360

Hence, among the given years, the total number of passed candidates is the least in 2015.

Hence, option (d).

Workspace:

**25. IIFT 2016 LRDI | DI - Tables & Graphs**

In which of the following years, Banga Kingdom recorded highest pass percentage?

- A.
2012

- B.
2013

- C.
2014

- D.
2016

Answer: Option C

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**Explanation** :

Here, the calculation is required only for Banga kingdom.

2012: (640/4000) × 100 = 16%

2013: (810/4500) × 100 = 18%

2014: (1235/6500) × 100 = 19%

2016: (660/6000) × 100 = 11%

Hence, the highest passing percentage is in 2014.

Hence, option (c).

Workspace:

**26. IIFT 2016 LRDI | DI - Tables & Graphs**

What is the overall pass percentage of all the kingdoms in the year 2013?

- A.
13.88

- B.
14.88

- C.
15.88

- D.
16.88

Answer: Option B

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**Explanation** :

Consider the solution to the earlier questions.

Total passed students = 3570

Total appeared students

= 5500 + 4500 + 2500 + 8000 + 3500 = 24000

∴ Total passing % of all kingdoms in 2013 = (3570/24000) × 100 = 14.88%

Hence, option (b).

Workspace:

**27. IIFT 2016 LRDI | DI - Tables & Graphs**

Highest number of candidates passed are from which of the following kingdoms for all the years together?

- A.
Anga

- B.
Banga

- C.
Gandhar

- D.
Dwarka

Answer: Option D

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**Explanation** :

Consider the solution to the earlier questions.

Total passed candidates from Anga = 4760

Now calculate this for the other three kingdoms in the options.

Banga: 640 + 810 + 1235 + 880 + 660 = 4225

Gandhar: 765 + 595 + 810 + 520 + 1200 = 3890

Dwarka: 780 + 1120 + 715 + 935 + 1330 = 4880

Hence, the maximum candidates passed from Dwarka.

Hence, option (d).

Workspace:

**Answer the following question based on the information given below.**

T-Nation, a T-shirt manufacturing company has unleashed 5-5-5 strategy, five brands (Ultimate Supreme, Smash, Paramount, Astute), five sizes, (S, M, L, XL, XXL), and five Stores (S1, S2, S3, S4, S5) to capture New Delhi market. Number of T-Shirts in each of the store is given in the stacked bar chart below.

**Note: **Visibility of a brand in a store is given by number of T-Shirts of the brand in the store by total number of T-Shirts in the store. Visibility across the stores is measured by sum of the scores of visibility of a brand in a store.

**28. IIFT 2016 LRDI | DI - Tables & Graphs**

Which brand of T-Shirt has more visibility across the stores?

- A.
Astute

- B.
Supreme

- C.
Paramount

- D.
Smash

Answer: Option B

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**Explanation** :

Since the first two questions of the set require you to find visibility of each brand in each store, you can make a table as under:

Hence, Supreme has the highest total visibility.

Hence, option (b).

Workspace:

**29. IIFT 2016 LRDI | DI - Tables & Graphs**

Which brand has lowest visibility score in any of the stores?

- A.
Astute

- B.
Smash

- C.
Paramount

- D.
Ultimate

Answer: Option A

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**Explanation** :

Since the first two questions of the set require you to find visibility of each brand in each store, you can make a table as under:

Astute has the lowest visibility score in store 3 i.e. 8.57.

Hence, option (a).

**Note: **This specific question can also be solved without the table, but we have made the table as it helps solve two questions directly.

To solve this, find the lowest stocked shirt per store.

e.g. 30 units of Ultimate and Smash is the lowest in Store 3 while 30 of Astute is the lowest in Store 4. Hence, for stores 3 and 4, these brands can have lowest visibility score. Total t-shirts in stores 3 and 4 is 280 and 350 respectively.

(30/280) > (30/350)

Hence, visibility of Astute in store 4 is lower than any brand in store 3.

Similarly, lowest visibility in other three stores is:

Store 1: (57/450); store 2: (48/440), store 5: (65/480)

By comparing these fractions with (30/350), you can conclude that Astute in store 3 still have lowest visibility score.

Workspace:

**30. IIFT 2016 LRDI | DI - Tables & Graphs**

Suppose, size M constitutes 22% of all the T-Shirts owned by T-nation. It is also given that ‘size M T-shirt’ in stores 1, 2 and 5 are 10% of the total T-shirts in these stores. Then, the total number of T-Shirts of size M in store 4 cannot be less than

- A.
23

- B.
28

- C.
32

- D.
44

Answer: Option A

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**Explanation** :

Total t-shirts owned by T-Nation = sum of total t-shirts across all stores.

Store 1 = 57 + 128 + 85 + 69 + 111 = 450

Store 2 = 84 + 55 + 137 + 116 + 48 = 440

Store 3 = 30 + 79 + 30 + 50 + 91 = 280

Store 4 = 48 + 111 + 60 + 101 + 30 = 350

Store 5 = 122 + 65 + 108 + 105 + 80 = 480

∴ Total t-shirts owned by T-Nation

= 450 + 440 + 280 + 350 + 480 = 2000

∴ Total t-shirts of size M = 22% of 2000 = 440

Total size M t-shirts in stores 1, 2 and 5 = 10% of (450 + 440 + 480) = 10% of 1370 = 137

∴ Total size M t-shirts in stores 3 and 4 = 440 – 137 = 303

Now, the minimum number of size M

t-shirts in store 4 has to be found. For this, as many t-shirts as possible should be in store 3.

Since total t-shirts in store 3 are 280, assume that all of them are size M.

∴ Minimum number of size M t-shirts in store 4 = 303 – 380 = 23

Hence, option (a).

Workspace:

**31. IIFT 2016 LRDI | DI - Tables & Graphs**

What is the approximate share of Supreme brand in all stores together?

- A.
19

- B.
22

- C.
18

- D.
20

Answer: Option B

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**Explanation** :

Total t-shirts owned by T-Nation = sum of total t-shirts across all stores.

Store 1 = 57 + 128 + 85 + 69 + 111 = 450

Store 2 = 84 + 55 + 137 + 116 + 48 = 440

Store 3 = 30 + 79 + 30 + 50 + 91 = 280

Store 4 = 48 + 111 + 60 + 101 + 30 = 350

Store 5 = 122 + 65 + 108 + 105 + 80 = 480

∴ Total t-shirts owned by T-Nation

= 450 + 440 + 280 + 350 + 480 = 2000

∴ Total t-shirts of size M = 22% of 2000 = 440

Total size M t-shirts in stores 1, 2 and 5 = 10% of (450 + 440 + 480) = 10% of 1370 = 137

∴ Total size M t-shirts in stores 3 and 4 = 440 – 137 = 303

Total t-shirts across all stores = 2000

Total t-shirts of Supreme brand = 128

+ 55 + 79 + 111 + 65 = 438

∴ Share of Supreme brand

= (438/2000) × 100 = 21.9% ≅ 22%

Hence, option (b).

Workspace:

**32. IIFT 2016 LRDI | DI - Tables & Graphs**

Approximately, by what percentage are Smash T-shirts greater than Ultimate T-shirts in all the stores together?

- A.
79

- B.
50

- C.
35

- D.
23

Answer: Option D

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**Explanation** :

Total Smash t-shirts = 85 + 137 + 30 + 60 + 108 = 420

Total Ultimate t-shirts = 57 + 84 + 30 + 48 + 122 = 341

∴Required percentage = ((420-341))/341×100=23.17%≈23%

Hence, option (d).

Workspace:

**Answer the following question based on the information given below.**

Given below is the data about Domestic Investment (DI) and Foreign Investment (FI) in 9 different sectors over 5 year period.(In Rs. Crores)

**Note: **DI = Domestic Investment; FI = Foreign Investment

**33. IIFT 2016 LRDI | DI - Tables & Graphs**

What is the approximate ratio of the total investment in Energy sector to that of Financial services sector?

- A.
1 : 1.2

- B.
3 : 4.5

- C.
1 : 0.5

- D.
2 : 3.8

Answer: Option A

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**Explanation** :

Total investment = total DI + total FI

For Energy: total

= (800 + 500 + 700 + 600 + 1100) + (1200 + 1400 + 2500 + 1000 + 500)

= 3700 + 6600 = 10300

For Financial Services: total

= (1800 + 400 + 1200 + 1000 + 700) + (500 + 2000 + 1600 + 1500 + 1400)

= 5100 + 7000 = 12100

∴ Required ratio = 10300 : 12100

= 103 : 121 ≅ 100 : 120 = 1 : 1.2

Hence, option (a).

Workspace:

**34. IIFT 2016 LRDI | DI - Tables & Graphs**

Absolute different between the Total DI and Total FI is highest for which sector?

- A.
Technology

- B.
Healthcare

- C.
Basic Material

- D.
None of the above

Answer: Option A

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**Explanation** :

Here, because one of the options is “None of the above”, you will need to calculate total DI and total FI for each sector.

Some data can already be found from the previous question.

Energy: DI ∼ FI = 6600 – 3700 = 2900

Financial Services: 7000 – 5100 = 1900

Now consider each option.

Technology: (2500 + 2800 + 5000 + 2000 + 4000) – (1500 + 1000 + 1500 + 1200 + 3000) = 16300 – 8200 = 8100

Healthcare: (3000 + 3000 + 6000 + 1500 + 600) – (2000 + 600 + 400 + 1000 + 3500) = 14100 – 7500 = 6600

Hence, option (b) can be eliminated.

Basic Material: (1500 + 1500 + 2500 + 2000 + 2500) – (800 + 1300 + 1400 + 900 + 800) = 10000 – 5200 = 4800

Hence, option (c) can be eliminated.

Among “None of the Above”, Energy and Financial Services can be ignored.

Only Communication Services, Consumer Cyclical, Consumer Defensive and Real Estate need to be compared with Technology (8100).

Communication Services: (2000 + 1200 + 1600 + 1000 + 500) – (1400 + 1000 + 1100 + 300 + 1200) = 6300 – 5000 = 1300

Hence, this can be ignored.

Consumer Cyclical: (1500 + 1500 + 3000 + 700 + 1900) – (1000 + 1200 + 1100 + 500 + 900) = 8600 – 4700 = 3900

Hence, this can also be ignored.

Consumer Defensive: (1300 + 700 + 1500 + 2000 + 1800) – (1000 + 1600 + 800 + 500 + 1600) = 7300 – 5500 = 1800

Hence, this can also be ignored.

Real Estate: (500 + 1000 + 4000 + 6000 + 2000) – (2000 + 1500 + 3000 + 1500 + 2100) = 13500 – 10100 = 2400

Hence, this can also be ignored.

Hence, all the sectors under “None of the above” have a lower value compared to Technology.

Hence, option (a).

Workspace:

**35. IIFT 2016 LRDI | DI - Tables & Graphs**

In which year the average DI is the highest?

- A.
2013

- B.
2011

- C.
2010

- D.
2009

Answer: Option A

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**Explanation** :

The average DI will be the highest for the year when the total DI is highest. Consider the four years given in the options.

2009: 1500 + 2000 + 1000 + 1300 + 800 + 1800 + 2000 + 500 + 1500 = 12400

2010: 1500 + 1200 + 1200 + 700 + 500 + 400 + 600 + 1000 + 1000 = 8100

2011: 2500 + 1600 + 1100 + 1500 + 700 + 1200 + 400 + 4000 + 1500 = 14500

2013: 2500 + 500 + 900 + 1800 + 1100 + 700 + 3500 + 2000 + 3000 = 16000

Hence, option (a).

Workspace:

**36. IIFT 2016 LRDI | DI - Tables & Graphs**

Which sector has received the 2nd lowest investment from DI for the total period?

- A.
Consumer cyclical

- B.
Consumer durable

- C.
Energy

- D.
None of the above

Answer: Option A

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**Explanation** :

The second lowest investment from DI is for Consumer Cyclical.

Hence, option (a).

Workspace:

**37. IIFT 2016 LRDI | DI - Tables & Graphs**

What is the approximate ratio of total DI to total FI?

- A.
1 : 1.10

- B.
2 : 2.36

- C.
0.75 : 1

- D.
0.75 : 1.5

Answer: Option B

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**Explanation** :

Total DI and FI can be found.

Total DI = 12400 + 8100 + 14500 + 15300 + 16000 = 66300

Total FI = 13900 + 16100 + 24400 + 9900 + 14100 = 78400

∴ Required ratio = 66300 : 78400 ≅ 0.84

This is closest to 2 : 2.36.

Hence, option (b).

Workspace:

**Answer the following question based on the information given below.**

The following 2 bar charts represent revenues and expenses (in thousands) of A Ltd, B Ltd, and C Ltd over a period of five years.

Profit = Revenues – Expenses

**38. IIFT 2016 LRDI | DI - Tables & Graphs**

For which company, the average annual expenses were maximum in the given period?

- A.
A Ltd

- B.
B Ltd

- C.
C Ltd

- D.
Both A Ltd and B Ltd

Answer: Option C

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**Explanation** :

The average annual expenses will be maximum for the company that has the maximum total expenses over the given period.

A: 105 + 185 + 100 + 120 + 110 = 620

B: 135 + 115 + 130 + 125 + 135 = 640

C: 165 + 155 + 190 + 100 + 100 = 710

Hence, option (c).

Workspace:

**39. IIFT 2016 LRDI | DI - Tables & Graphs**

For which year, the average annual revenue (considering all three companies) was the maximum?

- A.
2011

- B.
2012

- C.
2013

- D.
2014

Answer: Option B

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**Explanation** :

The average revenue will be highest for the year where total revenue is highest.

By observation, the maximum total revenue in 2012.

Hence, option (b).

Workspace:

**40. IIFT 2016 LRDI | DI - Tables & Graphs**

What was the approximate percentage decline in the revenue of C Ltd in 2015 as compared to the revenue in 2012?

- A.
16

- B.
25

- C.
33

- D.
40

Answer: Option C

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**Explanation** :

C (2015) = 120 and C (2012) = 180

∴ Required percentage

$=\frac{180-120}{180}\times 100=33.33\%$

Hence, option (c).

Workspace:

**41. IIFT 2016 LRDI | DI - Tables & Graphs**

What was the approximate absolute difference between the average revenue of A Ltd in 2011, 2012 and 2013 and the average revenue of B Ltd in 2013, 2014 and 2015?

- A.
20

- B.
160

- C.
20000

- D.
26000

Answer: Option C

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**Explanation** :

Average revenue of A = (120 + 165 + 135)/3 = 140

Average revenue of B = (165 + 150 + 165)/3 = 160

∴ Difference = 140 – 120 = 20 (in thousands) i.e. 20000

Hence, option (c).

Workspace:

**42. IIFT 2016 LRDI | DI - Tables & Graphs**

For which of the following years the percentage of rise/fall in profit from the previous year was the maximum for A Ltd?

- A.
2012

- B.
2013

- C.
2014

- D.
2015

Answer: Option B

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**Explanation** :

Profit/Loss for A in each year is:

2011 - 15 (profit); 2012 - –20 (loss); 2013 - 35 (profit); 2014 - 60 (profit); 2015 - 40 (profit)

Since the profit is increasing from (−20) to (35), the maximum percentage rise will be in this period i.e. in 2013.

Hence, option (b).

Workspace:

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