# IIFT 2015 LRDI | Previous Year IIFT Paper

Join our Telegram Group for CAT Preparation.

**Solve the questions based on the information provided in the passage below:**

Six engineers Anthony, Brad, Carla, Dinesh, Evan and Frank are offered jobs at six different locations –England, Germany, India, Australia, Singapore and UAE. The jobs offered are in six different branches, and are based on their competence as well as preference. The branches are IT, Mechanical, Chemical, Electronics, Metallurgy and Electrical, though not necessarily in the same order. Their placements are subject to the following conditions:

i. The engineer in the Electrical Department is not placed in Germany.

ii. Anthony is placed in Singapore while Dinesh in UAE.

iii. Frank is not in the Metallurgy Department but Brad is in the Chemical Department.

iv. Evan is placed in the Mechanical Department while Frank is offered a job in Australia.

v. The only department offering jobs in India is the Chemical Department while there are no vacancies for IT in Singapore.

vi. Anthony is interested in IT and Electrical Department while Frank is interested in IT and Mechanical Department. Both of them settle for the options available based on their interests in the locations allotted to them.

vii. In recent years, UAE has emerged as a hub for metallurgy exports and thus recruitment is done for the same while all mechanical posts are in England.

**1. IIFT 2015 LRDI | LR - Selection & Distribution**

Who joined the Electronics Department?

- A.
Dinesh

- B.
Anthony

- C.
Carla

- D.
Brad

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

Using all the statements, we can fill the following data directly,

From 5,

**Chemical Engineer is offered job in India.**

So, Brad is offered job in India

Hence, **Carla is offered job at Germany.**

From 4 and 6,

Evan is from Mechanical branch,

So, **Frank is from IT branch;**

Hence, **Anthony is from Electrical branch** and **Carla is from Electronics branch.**

So the final arrangement is,

From the table we get,

Carla is the one from electronics department.

Hence, option (c).

Workspace:

**2. IIFT 2015 LRDI | LR - Selection & Distribution**

The person placed in UAE is in the _____________ Department

- A.
Electronics

- B.
Mechanical

- C.
Metallurgy

- D.
Chemical

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

Using all the statements, we can fill the following data directly,

From 5,

**Chemical Engineer is offered job in India.**

So, Brad is offered job in India

Hence, **Carla is offered job at Germany.**

From 4 and 6,

Evan is from Mechanical branch,

So, **Frank is from IT branch;**

Hence, **Anthony is from Electrical branch** and **Carla is from Electronics branch.**

So the final arrangement is,

From the table we get,

The person in UAE has Metallurgy branch.

Hence, option (c).

Workspace:

**3. IIFT 2015 LRDI | LR - Selection & Distribution**

Out of the following, which is the correct combination?

- A.
Anthony-Germany-Electrical

- B.
Brad-India-Chemical

- C.
Evan-England-Electronics

- D.
Frank-Australia-Metallurgy

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

Using all the statements, we can fill the following data directly,

From 5,

**Chemical Engineer is offered job in India.**

So, Brad is offered job in India

Hence, **Carla is offered job at Germany.**

From 4 and 6,

Evan is from Mechanical branch,

So, **Frank is from IT branch;**

Hence, **Anthony is from Electrical branch** and **Carla is from Electronics branch.**

So the final arrangement is,

From the table we get,

Brad -India -Chemical is the correct combination.

Hence, option (b).

Workspace:

**4. IIFT 2015 LRDI | LR - Selection & Distribution**

Who joined the IT Department in Australia?

- A.
Frank

- B.
Carla

- C.
Evan

- D.
Brad

Answer: Option A

Join our Telegram Group for CAT Preparation.

**Explanation** :

Using all the statements, we can fill the following data directly,

From 5,

**Chemical Engineer is offered job in India.**

So, Brad is offered job in India

Hence, **Carla is offered job at Germany.**

From 4 and 6,

Evan is from Mechanical branch,

So, **Frank is from IT branch;**

Hence, **Anthony is from Electrical branch** and **Carla is from Electronics branch.**

So the final arrangement is,

From the table we get,

Frank joined IT Department in Australia.

Hence, option (a).

Workspace:

**5. IIFT 2015 LRDI | LR - Selection & Distribution**

Which combination is true for Dinesh?

- A.
India-Electrica

- B.
UAE-Electronics

- C.
England-Metallurgy

- D.
England-Metallurgy

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

Using all the statements, we can fill the following data directly,

From 5,

**Chemical Engineer is offered job in India.**

So, Brad is offered job in India

Hence, **Carla is offered job at Germany.**

From 4 and 6,

Evan is from Mechanical branch,

So, **Frank is from IT branch;**

Hence, **Anthony is from Electrical branch** and **Carla is from Electronics branch.**

So the final arrangement is,

From the table we get,

Dinesh - UAE – Electronics is the correct combination.

Hence, option (d).

Workspace:

**6. IIFT 2015 LRDI | LR - Logical Connectives**

Based on the given statement, choose the right conclusion:‘If the breakfast doesn’t have eggs, I will not go for a walk and will not have lunch.’

- A.
If I went for a walk and didn’t have lunch, the breakfast didn’t have eggs.

- B.
If I went for a walk or I had lunch, the breakfast had eggs.

- C.
If I went for a walk or I had no lunch, the breakfast had eggs.

- D.
If I didn’t go for a walk and had lunch, the breakfast had eggs.

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

Let,

A = The breakfast doesn't have eggs

B = I will not go for a walk and will not have lunch.

From the logical deductions,

AB = ~B~A

Also, and is replaced by or and vice versa.

So,

~A = The breakfast has eggs.

~B = I will go for a walk or will have lunch.

So, we get,

~B~A = I will go for a walk or will have lunch, the breakfast has eggs.

Hence, option (b).

Workspace:

**Read the details below and answer the questions that follow.**

Due to astrological reasons, a mother named all her daughters with the alphabet ‘K’ as Kamla, Kamlesh, Kriti, Kripa, Kranti and Kalpana.

i. Kamla is not the tallest while Kripa is not the most qualified.

ii. The shortest is the most qualified amongst them all.

iii. Kalpana is more qualified than Kamlesh who is more qualified than Kriti.

iv. Kamla is less qualified than Kamlesh but is taller than Kamlesh.

v. Kalpana is shorter than Kriti but taller than Kranti.

vi. Kriti is more qualified than Kamla while Kamlesh is taller than Kriti.

vii. Kripa is the least qualified amongst the daughters.

**7. IIFT 2015 LRDI | LR - Selection & Distribution**

Who is the third tallest starting in decreasing order of height?

- A.
Kamla

- B.
Kamlesh

- C.
Kriti

- D.
Kranti

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

Let us rank their heights and their qualification on a scale from 1 to 6.

Rank 1 is the tallest and the most qualified and Rank 6 is the shortest and the least qualified.

Kamla is not the tallest. So Kamla's height can be any rank from 2 to 5.

Kripa is the least qualified amongst the daughters. So Kripa_{Q }_{= }6 (sub-script Q and H denote rank for qualification and height respectively).

From st iv, v and vi, we conclude that

Kamla_{H} > Kamlesh_{H} > Kriti_{H} > Kalpana_{H }> Kranti_{H}

But Kamla is not be the tallest. Therefore Kripa is the tallest and Kamla is the 2^{nd }tallest and the order follows as shown above.

From St ii, Kranti_{Q }= 1.

From St iii and from st vi, we conclude that

Kalpana_{Q} > Kamlesh_{Q} >Kriti_{Q} >Kamla_{Q}

Therefore on the basis of the qualification,

Kalpana's rank is 2, Kamlesh's rank is 3, Kriti's rank is 4 and Kamla's rank is 5.

The following table can be regarding their height and qualification:

Decreasing order of height are the ranks starting from 1 upto 6.

Third tallest amongst all is Kamlesh

Hence, option (b).

Workspace:

**8. IIFT 2015 LRDI | LR - Selection & Distribution**

Who is the most qualified?

- A.
Kamlesh

- B.
Kriti

- C.
Kripa

- D.
Kranti

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

Most qualified is the person with rank 1.

The person with rank 1 is Kranti.

Hence, option (d).

Workspace:

**9. IIFT 2015 LRDI | LR - Selection & Distribution**

What is the rank of Kriti in increasing order of qualification?

- A.
2

- B.
3

- C.
5

- D.
4

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

The ranks in the increasing order of qualification are from 6 to 1.

Kriti's rank in decreasing order of qualification is 4.

Therefore Kriti's rank in the increasing order of qualification is 3.

Hence, option (b).

Workspace:

**10. IIFT 2015 LRDI | LR - Selection & Distribution**

What is the rank of Kamla in increasing order of height?

- A.
3

- B.
5

- C.
4

- D.
2

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

The ranks in the increasing order of height are from 6 to 1.

Kamla's rank in decreasing order of height is 2.

Therefore Kamla's rank in increasing order of height is 5.

Hence, option (b).

Workspace:

**11. IIFT 2015 LRDI | LR - Series**

Based on the number series given, fill in the missing number.18, 37, 76, 155, ________, 633, 1272

- A.
322

- B.
314

- C.
341

- D.
250

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

The Pattern here is,

18 × 2 + 1 = 37,

37 × 2 + 2 = 76,

76 × 2 + 3 = 155,

So,

155 × 2 + 4 = 314,

314 × 2 + 5 = 633,

633 × 2 + 6 = 1272,

Hence, option (b).

Workspace:

**Based on the conditions stated in the passage below, answer the questions that follow.**

There are three countries, USA, UAE and UK. An exporter can select one country or two countries or all the three countries subject to the conditions below:

Condition 1: Both USA and UAE have to be selected.

Condition 2: Either USA or UK, but not both have to be selected.

Condition 3: UAE can be selected only if UK has been selected.

Condition 4: USA can be selected only if UK is selected.

**12. IIFT 2015 LRDI | LR - Selection & Distribution**

How many countries can be selected if no condition is imposed?

- A.
6

- B.
4

- C.
7

- D.
8

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

If no condition is imposed then we can select countries in 23 – 1 = 7 ways.

So, we have total 7 combinations.

Hence, option (c).

Note:- This question is ambiguous, as it is asking number of countries. In that case, we can select only 3 countries. But we don't have options. So here we are assuming number different combinations are asked.

Workspace:

**13. IIFT 2015 LRDI | LR - Selection & Distribution**

How many countries can be selected to meet only condition 1?

- A.
0

- B.
2

- C.
1

- D.
3

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

If only condition 1 is imposed then we can select,

USA-UAE and USA-UAE-UK.

So, we have two combination.

Hence, option (b).

**Note: **This question is ambiguous, as it is asking number of countries. In that case, we can select 2 or 3 countries. But we don't have options. So here we are assuming number of different combinations are asked.

Workspace:

**14. IIFT 2015 LRDI | LR - Selection & Distribution**

How many countries can be selected to meet only conditions 2 and 3?

- A.
0

- B.
2 or 1

- C.
0 or 1

- D.
None of these

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

If only condition 2 and 3 are imposed then we can select,

UK-UAE, USA, USA-UAE.

So, we can select 1 or 2 countries considering all possible combinations.

Hence, option (b).

Workspace:

**15. IIFT 2015 LRDI | LR - Blood Relation**

Based on the following relations, which of the given options indicate that W is the niece of X?A+B means that A is the brother of B.

A*B means that A is the father of B.

A-B means that A is the sister of B.

- A.
X+Y+Z-W

- B.
Z-W*Y+X

- C.
X+Y*W-Z

- D.
X*Y+W-Z

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

From the question W is the niece of X, So W is a female.

In option A, We see that all X , Y , Z and W are brothers and sisters.

In option B, W is father of Y. So, W is a male.

Consider option C.

It says X is Y's brother, Y is W's father and W is Z's sister.

Hence W is X's niece.

Hence, option (c).

Workspace:

**16. IIFT 2015 LRDI | LR - Directions**

Alex walks 1 mile towards East and then he turns towards South and walks further 5 miles. After that he turns East and walks 2 miles further. Finally he turns to his North and walks 9 miles. How far is he from the starting point?

- A.
25 miles

- B.
2 miles

- C.
5 miles

- D.
4 miles

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

From the figure, the final position is E and the starting point is D.

Distance DT = Distance DF + Distance FT

= Distance DF + Distance HP

= 1 + 2

= 3 miles.

Distance ET = DistanceEP – Distance TP

= Distance EP – Distance FH

= 9 – 5

= 4 miles

From the figure, the distance between starting point and the end point is

(DE)2 = 32 + 42

= 9 + 16

= 25

DE = 5 miles

Hence, option (c).

Workspace:

**17. IIFT 2015 LRDI | LR - Syllogisms**

**From the given statements, choose the conclusions which follow logically:**

**Statements:**

i. Some iphones are mobiles

ii. Some mobiles are ipads

iii. Some ipads are tablets

**Conclusions:**

I. Some tablets are iphones

II. Some mobiles are tablets

III. Some ipads are iphones

IV. All iphones are tablets

- A.
Only I & II follow

- B.
Only I, II & III follow

- C.
Only II & III follow

- D.
None of these

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

The statements i, ii and iii can be represented as shown above

From the figure, Set of iphones do not intersect with the set of ipads and the set of tablets, and the set of mobiles do not intersect with the set of tablets.

Consider the conclusions,

From the figure, first three conclusions are not true. In this set, the fourth conclusion cannot be concluded.

Hence, option (d).

Workspace:

**Read the passage below and answer the questions that follow.**

Export cargo of a trader can go through seven cities P, Q, R, S, T, U and V. The following cities have a two way connection i.e., Cargo can move in both directions between them; S and U, P and Q, Q and R, V and T, R and T, V and U. Cargo can move only in one direction from U to Q.

**18. IIFT 2015 LRDI | DI - Routes & Networks**

If the trader wants the cargo to move from City S to City T then excluding cities S and T, what is the minimum number of cities that the cargo has to cross in transit?

- A.
4

- B.
3

- C.
2

- D.
5

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

From the figure, Excluding cities S and T cargo can go from city S to city T in 2 ways i.e S-U-Q-R-T and S-U-V-T. The shortest path from S to T is S-U-V-T. Therefore the minimum number of cities that the cargo has to cross in transit is 2.

Hence, option (c).

Workspace:

**19. IIFT 2015 LRDI | DI - Routes & Networks**

If the trader wants the cargo to go to City U from City P through the longest route, how many cities will he be required to cross (excluding cities P and U)?

- A.
2

- B.
4

- C.
3

- D.
5

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

From the figure, Cargo can go from city P to city U in only one possible way i.e. P-Q-R-T-V-U. Going through this path, the cargo will have to pass through 4 cities.

Hence, option (b).

Workspace:

**20. IIFT 2015 LRDI | DI - Routes & Networks**

To move cargo from City P to City U, which of the following statements will minimise the number of cities to be crossed in transit?

- A.
Connect cities U to R with a two way connection

- B.
Connect cities P to S with a one way connection from cities S to P

- C.
Connect cities U to Q with a two way connection

- D.
Connect cities R to V with a two way connection

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

Consider option A. The path is P-Q-R-U. We have to cross 2 intermediate cities in it.

Consider option B. If we connect cities from P to S with a one way connection from cities S to P. The path formed will be P-Q-R-T-V-U. It becomes a longer path than option A.

Using option C, the path formed is the shortest path. The path formed is P-Q-U. This smaller than that in option A.

Consider option D. The path formed using option D is longer compared to the path formed using option C. Hence options A, B, and D are eliminated.

Hence, option (c).

Workspace:

**Read the following information and tables and answer the questions that follow.**

Torrent Enterprises sells air conditioners of Eagle Brand in the retail market of Delhi. The month-wise total number of Window Air Conditioner (WAC) units sold by Torrent during April 2014 to March 2015 are shown below in Table A. Table B shows the share of different types of WACs in total monthly sales for the said period.

Number of Units Sold by Torrent Enterprises During the Period April 14 to March 15

**Performance measures are as follows:**

**Half Yearly Sales Performance: **$\frac{\mathrm{ct}14\mathrm{to}\mathrm{Mar}15\mathrm{Average}\mathrm{Sales}-\mathrm{April}14\mathrm{to}\mathrm{Sep}14\mathrm{Average}\mathrm{Sales}}{\mathrm{April}14\mathrm{to}\mathrm{Sep}14\mathrm{Average}\mathrm{Sales}}$

**Monthly Sales Performance: **$\frac{\mathrm{Current}\mathrm{Month}\mathrm{Sales}-\mathrm{Previous}\mathrm{Month}\mathrm{Sales}}{\mathrm{Previous}\mathrm{Month}\mathrm{Sales}}$

**Sales Volatility: **$\frac{\mathrm{Maximum}\mathrm{Monthly}\mathrm{Sales}-\mathrm{Minimum}\mathrm{Monthly}\mathrm{Sales}}{\mathrm{Average}\mathrm{Monthly}\mathrm{Sales}}$

**21. IIFT 2015 LRDI | DI - Tables & Graphs**

What is the closest average number of 1½ ton Window ACs sold by Torrent Enterprises during April 2014 - March 2015?

- A.
342

- B.
338

- C.
350

- D.
330

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

Sum of 1½ ton Window ACs sold by Torrent Enterprises during April 2014 – March 2015

= 0.19(Sum of number of units sold in April-14, May-14, Sep-14, Feb-15, Mar-15 and Aug-14) + 0.33(Sum of number of units sold in Jun-14, Jul-14, Dec-14, Oct-14, Nov-14 and Jan-15)

= 0.19 × (1266 +1268 + 1296 + 1340 + 1350 + 1296) + 0.33 × (1272 + 1292 + 1300 + 1298 + 1300 + 1330)

= 0.19 × 7816 + 0.33 × 7772 = 1485.04 + 2571.36 ≈ 338

Hence, option (b).

Workspace:

**22. IIFT 2015 LRDI | DI - Tables & Graphs**

The absolute difference between average annual sales (in units) of which pair of WACs type is the highest

- A.
1 Ton and ½ Ton

- B.
1 Ton and 2 Ton

- C.
2 Ton and ½ Ton

- D.
1½ Ton and ½ Ton

Answer: Option A

Join our Telegram Group for CAT Preparation.

**Explanation** :

Units sold in Apr-14, May-14 and Sep-14 = 3830

Units sold in Jun-14, Jul-14 and Dec-14 = 3864

Units sold in Aug-14, Feb-15 and Mar-15 = 3986

Units sold in Oct-14, Nov-14 and Jan-15 = 3928

Thus, the absolute difference between average annual sales (in units) of 1 ton and ½ ton is maximum.

Hence, option (a).

Workspace:

**23. IIFT 2015 LRDI | DI - Tables & Graphs**

Which type of WAC has performed the second best in Half Yearly Sales Performance?

- A.
½ Ton

- B.
1 Ton

- C.
1½ Ton

- D.
2 Ton

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

Sales for various WAC types from Oct-14 to Mar-15:

Two ton: 0.25 × 1300 + 0.31(1340 + 1350) + 0.25(3928) = 2141

One & Half ton: 0.33 × 1300 + 0.19(1340 + 1350) + 0.33(3928) = 2236

One ton: 0.12 × 1300 + 0.34(1340 + 1350) + 0.26(3928) = 2092

One & Half ton: 0.3 × 1300 + 0.16(1340 + 1350) + 0.16(3928) = 1449

Referring to previous solution, the sales for various WAC types from Apr-14 to Sep-14:

Two ton: 3950 – 2141 = 1809

One & Half ton: 4056 – 2236 = 1820

One ton: 3376 – 2092 = 1284

One & Half ton: 4226 – 1449 = 2777

Half yearly sales performance for various types is:

$2ton=\frac{\left({\displaystyle \frac{2141}{6}}\right)-\left({\displaystyle \frac{1809}{6}}\right)}{\left({\displaystyle \frac{1809}{6}}\right)}$

$=\frac{2141-1809}{1809}\approx 0.18$

$1\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.ton=\frac{2236-1820}{1820}\approx 0.23$

1 ton $=\frac{2092-1284}{1284}\approx 0.63$

$\frac{1}{2}ton=\frac{1449-2777}{2777}\approx -0.48$

Thus, second best performance in Half Yearly Sales Performance is of 1½ ton WACs.

Hence, option (c).

Workspace:

**24. IIFT 2015 LRDI | DI - Tables & Graphs**

In which of the months given below, the total WAC Monthly Sales Performance was the highest?

- A.
May 2014

- B.
June 2014

- C.
October 2014

- D.
February 2015

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

Monthly sales performance:

i. May 2014 = 2/1266

ii. June 2014 = 4/1268

iii. October 2014 = 2/1296

iv. February 2015 = 10/1330

10/1330 is the highest fraction.

Hence, option (d).

Workspace:

**25. IIFT 2015 LRDI | DI - Tables & Graphs**

Which type of WAC has the least Sales Volatility?

- A.
½ Ton

- B.
1 Ton

- C.
1½ Ton

- D.
2 Ton

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

Sales volatility of 2 ton WAC

$=\frac{419-253}{329}\approx 0.5$

Sales volatility of 1^{1}/_{2} ton WAC

$=\frac{439-241}{338}\approx 0.59$

Sales volatility of 1 ton WAC

$=\frac{459-153}{281}\approx 1.09$

Sales volatility of^{ 1}/_{2} ton WAC

$=\frac{609-207}{352}\approx 1.14$

Thus, 2 ton of WAC has the least Sales Volatility.

Hence, option (d).

Workspace:

**Read the following information, graph and table and answer the questions that follow.**

Ellen Inc. is a Mumbai based company which sells five products branded as A, B, C, D and E in India. Anita looks after entire sales of North India working from regional office in Delhi. She was preparing for annual review meeting scheduled next day in Mumbai. She was attempting to analyse sales in North India for the seven year period from 2009 to 2015. She first calculated average sales in rupees of all the five brands and constructed a table exhibiting the difference between average sales of each pair of brands as shown in the following table:

**Difference Between Average Sales of Products for the 7 year period 2009-15 in Rs Crores**

After taking a print out of the above table, she attempted to look at the trend of sales and plotted a graph in MS Excel. Later she took a print out of the graph and left for a meeting. While on her way she figured out that due to some printer cartridge problem sales of Product A in 2013, Product C in 2010, and Product D in 2012 were not visible in the graph as reproduced below. Anita had to make some quick calculations to arrive at the information outlined in the following questions:

**26. IIFT 2015 LRDI | DI - Tables & Graphs**

What are the sales of Product A in 2013, Product C in 2010 and Product D in 2012?

- A.
Rs. 550 Crores, Rs. 800 Crores and Rs. 500 Crores

- B.
Rs. 500 Crores, Rs. 700 Crores and Rs. 600 Crores

- C.
Rs. 500 Crores, Rs. 800 Crores and Rs. 600 Crores

- D.
Rs. 4000 Crores, Rs. 800 Crores and Rs. 600 Crores

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

The first table gives the difference between the average sales of various products over seven years.

e.g. A – B = 214.29 crores

Hence, total difference between A and B over the seven year period is:

A – B = 214.29 × 7 = 1500 crores

Similarly,

C – A = 900 cr, A – D = 1000 cr, A – E = 300 cr, C – B = 2400 cr, D – B = 500 cr, E – B

= 1200 cr, C – D = 1900 cr, C – E = 1200 cr,

E – D = 700 cr

Let the sales of A in 2013 be *a*(‘000s), C in 2010 be *c*(‘000s) and D in 2012 be *d*(‘000s).

The total sales, by volume, of each product are:

A = (6800 + *a*) × 10^{3}

B = 5800 × 10^{3}

C = (7400 + *c*) × 10^{3}

D = (5700 + *d*) × 10^{3}

E = 7000 × 10^{3}

Hence, difference between number of units sold of B and E = 1200 × 10^{3}

Assuming that each product is sold at the same cost in each year,

Cost per product = (1200 cr)/(1200 thousand) = (1200 × 10^{7})/ (1200 × 10^{3})

= 10000

∴ Total sales of B over the given period = 5800 × 10^{3 }× 10000 = 5800 × 10^{7 }= 5800 crores

Similarly, total sales of E over the given period = 7000 × 10^{3 }× 10000 = 7000 × 10^{7 }= 7000 crores

Using these values in the equations above, A = 7300 crores, C = 8200 crores, D

= 6300 crores

Also, total sales of A = (6800 + *a*) × 10^{3 }× 10000 = (6800 + *a*) × 10^{7}

= (6800 + *a*) crores

Comparing this value with 7300 crores (found as total sales of A earlier),

*a* = 7300 – 6800 = 500 crores

Similarly, *c* = 800 crores and *d*

= 600 crores

Hence, option (c).

Workspace:

**27. IIFT 2015 LRDI | DI - Tables & Graphs**

Annual sales average of all products is the least in which year?

- A.
2010

- B.
2011

- C.
2012

- D.
2013

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

Because the cost per product is assumed to be the same for each product for each year, the average sales (or total sales) for any year across products can be found on the basis of units sold itself.

i.e., the year with highest units sold will also have highest average annuals sales.

2010: 500 + 600 + c + 1200 + 1600

= 3900 + c = 3900 + 800 = 4700

2011: 800 + 600 + 1400 + 1100 + 300 = 4200

2012: 1200 + 1000 + 1500 + d + 200

= 3900 + d = 3900 + 600 = 4500

2013: a + 1000 + 800 + 100 + 2000 = a + 3900 = 4400

Thus, the minimum sales are in 2011.

Hence, option (b).

Workspace:

**28. IIFT 2015 LRDI | DI - Tables & Graphs**

Which product has the least average sales for the seven year period 2009-15?

- A.
Product A

- B.
Product B

- C.
Product D

- D.
Product E

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

The first table gives the difference between the average sales of various products over seven years.

e.g. A – B = 214.29 crores

Hence, total difference between A and B over the seven year period is:

A – B = 214.29 × 7 = 1500 crores

Similarly,

C – A = 900 cr, A – D = 1000 cr, A – E = 300 cr, C – B = 2400 cr, D – B = 500 cr, E – B

= 1200 cr, C – D = 1900 cr, C – E = 1200 cr,

E – D = 700 cr

Let the sales of A in 2013 be *a*(‘000s), C in 2010 be *c*(‘000s) and D in 2012 be *d*(‘000s).

The total sales, by volume, of each product are:

A = (6800 + *a*) × 10^{3}

B = 5800 × 10^{3}

C = (7400 + *c*) × 10^{3}

D = (5700 + *d*) × 10^{3}

E = 7000 × 10^{3}

Hence, difference between number of units sold of B and E = 1200 × 10^{3}

Assuming that each product is sold at the same cost in each year,

Cost per product = (1200 cr)/(1200 thousand) = (1200 × 10^{7})/ (1200 × 10^{3})

= 10000

∴ Total sales of B over the given period = 5800 × 10^{3 }× 10000 = 5800 × 10^{7 }= 5800 crores

Similarly, total sales of E over the given period = 7000 × 10^{3 }× 10000 = 7000 × 10^{7 }= 7000 crores

Using these values in the equations above, A = 7300 crores, C = 8200 crores, D

= 6300 crores

Also, total sales of A = (6800 + *a*) × 10^{3 }× 10000 = (6800 + *a*) × 10^{7}

= (6800 + *a*) crores

The product having the least total sales over the given period will also have the least average.

Hence, this product is B, with total sales of Rs. 5800 crores.

Hence, option (b).

Workspace:

**29. IIFT 2015 LRDI | DI - Tables & Graphs**

The difference between average sales of products for the period 2009-15 is the least for which pair of products?

- A.
Product A and Product B

- B.
Product B and Product C

- C.
Product C and Product D

- D.
Product D and Product E

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

This question can be directly answered from the table given in the question.

The least difference between average sales (among the given options) is between products D and E.

Hence, option (d).

Workspace:

**30. IIFT 2015 LRDI | DI - Tables & Graphs**

f Year on Year (YoY) Growth is

$\left\{\frac{\mathrm{Current}\mathrm{Year}\mathrm{Sales}-\mathrm{Previous}\mathrm{Year}\mathrm{Sales}}{\mathrm{Previous}\mathrm{Year}\mathrm{Sales}}\right\}$

then the YoY growth of combined sales of all products has suffered maximum decline in which year?

- A.
2010

- B.
2011

- C.
2013

- D.
2015

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

The first table gives the difference between the average sales of various products over seven years.

e.g. A – B = 214.29 crores

Hence, total difference between A and B over the seven year period is:

A – B = 214.29 × 7 = 1500 crores

Similarly,

C – A = 900 cr, A – D = 1000 cr, A – E = 300 cr, C – B = 2400 cr, D – B = 500 cr, E – B

= 1200 cr, C – D = 1900 cr, C – E = 1200 cr,

E – D = 700 cr

Let the sales of A in 2013 be *a*(‘000s), C in 2010 be *c*(‘000s) and D in 2012 be *d*(‘000s).

The total sales, by volume, of each product are:

A = (6800 + *a*) × 10^{3}

B = 5800 × 10^{3}

C = (7400 + *c*) × 10^{3}

D = (5700 + *d*) × 10^{3}

E = 7000 × 10^{3}

Hence, difference between number of units sold of B and E = 1200 × 10^{3}

Assuming that each product is sold at the same cost in each year,

Cost per product = (1200 cr)/(1200 thousand) = (1200 × 10^{7})/ (1200 × 10^{3})

= 10000

∴ Total sales of B over the given period = 5800 × 10^{3 }× 10000 = 5800 × 10^{7 }= 5800 crores

Similarly, total sales of E over the given period = 7000 × 10^{3 }× 10000 = 7000 × 10^{7 }= 7000 crores

Using these values in the equations above, A = 7300 crores, C = 8200 crores, D

= 6300 crores

Also, total sales of A = (6800 + *a*) × 10^{3 }× 10000 = (6800 + *a*) × 10^{7}

= (6800 + *a*) crores

The same concept can be used for this question.

The values for 2010, 2011, 2012 and 2013 were already known.

Based on the options, find the values for 2009, 2014 and 2015.

2009: 1200 + 300 + 1500 + 600 + 1300

= 4900

2014: 1800 + 700 + 1200 + 900 + 1300

= 5900

2015: 1300 + 1600 + 1000 + 1800 + 300

= 6000

Since the sales increase from 2014 to 2015, option 4 can be directly eliminates as we need to find % decline.

For the other three values, it can be observed that the maximum % decline is in 2011.

Hence, option (c).

Workspace:

**Read the following information and graph and answer the questions that follow.**

An international Organisation produces a Competitive Index of countries every two years based on eight factors (Institutions, Infrastructure, Macroeconomic Environment, Higher Education, Market Efficiency, Technological Readiness, Business Sophistication and Innovation). The last three indices were developed in 2010, 2012 and 2014. The scores for all eight factors of XYZ country are shown in the graph below:

**31. IIFT 2015 LRDI | DI - Tables & Graphs**

If Factor performance is measured as 0.30 × Factor Score in 2014 + 0.35 × Factor Score in 2012 + 0.35 × Factor Score in 2010, then which of the following has best Factor Performance?

- A.
Innovation

- B.
Business Sophistication

- C.
Infrastructure

- D.
Macroeconomic Environment

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

Factor performance

= 0.3 × Factor score in 2014 + 0.35 × Factor score of 2012 + 0.35 × Factor score in 2010

Among the given options, Factor score of Macroeconomic Environment is the highest for 2010 and 2014.

For the year 2012, Factor Score of Business Sophistication is the highest and that of Macroeconomic Environment is second highest.

Thus, by comparing the values of Business Sophistication and Macroeconomic Environment, it can be concluded that Macroeconomic Environment has the best Factor Performance.

Hence, option (d).

Workspace:

**32. IIFT 2015 LRDI | DI - Tables & Graphs**

If Factor Performance is measured as

$\left\{\frac{\mathrm{Factor}\mathrm{Score}2014-\mathrm{Factor}\mathrm{Score}2012}{\mathrm{Factor}\mathrm{Score}2010}\right\}$

then which of the following has best Factor Performance?

- A.
nnovation

- B.
Business Sophistication

- C.
Infrastructure

- D.
Macroeconomic Environment

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

From the graph, it is clear that among the given options, the difference between the Factor Score of 2014 and Factor Score of 2012 is maximum and the Factor Score of 2010 is the least for Infrastructure.

Therefore, Infrastructure has the best Factor Performance.

Hence, option (c).

Workspace:

**33. IIFT 2015 LRDI | DI - Tables & Graphs**

Which of the following factors has the highest average score across indices of 2010, 2012 and 2014?

- A.
Infrastructure

- B.
Institutions

- C.
Technological Readiness

- D.
Market Efficiency

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

By observation,

i. Sum of Factor Scores of Infrastructure > Sum of Factor Scores of Technological Readiness

ii. Sum of Factor Scores of Institutions > Sum of Factor Scores of Market Efficiency

So, it is sufficient to compare values of Infrastructure and Institution.

The total score for Infrastructure

= 4 + 4 + 5.25 = 13.25

The total score for Institution

= 4.25 + 4.75 + 4.5 = 13.5

Therefore, Institutions has the highest average across indices of 2010, 2012 and 2014.

Hence, option (b).

Workspace:

**34. IIFT 2015 LRDI | DI - Tables & Graphs**

Which among the following factors had the least growth rate in 2014 versus scores of 2010?

- A.
Business Sophistication

- B.
Institutions

- C.
Technological Readiness

- D.
Infrastructure

Answer: Option B

Join our Telegram Group for CAT Preparation.

**Explanation** :

Among the given options, the difference between Factor Score in 2014 and that in 2010 is minimum for Institutions.

Hence, option (b).

Workspace:

**Read the following information and the accompanying graphs to answer the questions that follow.**

www.jay.com spent $ 5,57,000 during last 12 months for online display advertisements, also called impressions, on five websites (Website A, Website B, Website C, Website D and Website E). In this arrangement, www.jay.com is the Destination Site, and the five websites are referred to as the Ad Sites. The allocation of online display advertising expenditure is shown in Graph A. The online display advertisements helped www.jay.com to get visitors on its site. Online visitors, visiting the Ad Sites, are served display advertisements of www.jay.com and on clicking they land on the Destination Site (Graph B). Once on the Destination Site, some of the visitors complete the purchase process(Graph C)

$\mathrm{Quality}\mathrm{traffic}=\frac{\mathrm{No}.\mathrm{of}\mathrm{site}\mathrm{visitors}\mathrm{who}\mathrm{start}\mathrm{purchase}\mathrm{on}\mathrm{destination}\mathrm{site}}{\mathrm{No}.\mathrm{of}\mathrm{site}\mathrm{visitors}\mathrm{who}\mathrm{click}\mathrm{the}\mathrm{online}\mathrm{display}\mathrm{advertisement}}$

$\mathrm{Leakage}\mathrm{in}\mathrm{online}\mathrm{buying}=1-\frac{\mathrm{Complete}\mathrm{buying}\mathrm{on}\mathrm{the}\mathrm{destination}\mathrm{website}}{\mathrm{Start}\mathrm{buying}\mathrm{on}\mathrm{the}\mathrm{destination}\mathrm{website}}$

Efficiency of online display advertising expenditure on an Ad Site

$=\frac{\mathrm{No}.\mathrm{of}\mathrm{visitors}\mathrm{from}\mathrm{the}\mathrm{Ad}\mathrm{site}\mathrm{who}\mathrm{complete}\mathrm{the}\mathrm{purchase}\mathrm{process}}{\mathrm{Amount}\mathrm{spent}\mathrm{on}\mathrm{the}\mathrm{Ad}\mathrm{site}}$

**35. IIFT 2015 LRDI | DI - Tables & Graphs**

Which of following Ad Sites provide facility of least cost per advertisement?

- A.
Website A

- B.
Website B

- C.
Website D

- D.
Website E

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

www.jay.com spent $(27% of 557000) for 240 impressions.

So, cost per advertisement on Website A = 0.27 × 557000/240 ≈ $ 626.63

Similarly,

Cost per advertisement on Website B = 0.22 × 557000/370 ≈ $ 331.19

Cost per advertisement on Website D = 0.13 × 557000/300 ≈ $ 241.37

Cost per advertisement on Website E = 0.20 × 557000/150 ≈ $ 742.67

Thus, Website D provide facility of least cost per advertisement.

Hence, option (c).

Workspace:

**36. IIFT 2015 LRDI | DI - Tables & Graphs**

Which Ad Site has provided maximum quality traffic?

- A.
Website A

- B.
Website B

- C.
Website D

- D.
Website E

Answer: Option D

Join our Telegram Group for CAT Preparation.

**Explanation** :

Quality traffic provided by:

$\mathrm{Website}\mathrm{A}=\frac{2800}{120}=23.33$

$\mathrm{Website}\mathrm{B}=\frac{2500}{60}=41.67$

$\mathrm{Website}\mathrm{D}=\frac{3000}{80}=37.5$

$\mathrm{Website}\mathrm{E}=\frac{3500}{40}=87.5$

Thus, Website E has provided maximum quality traffic.

Hence, option (d).

Workspace:

**37. IIFT 2015 LRDI | DI - Tables & Graphs**

Which Ad Site sent traffic to www.jay.com with maximum leakage?

- A.
Website B

- B.
Website C

- C.
Website D

- D.
Website E

Answer: Option C

Join our Telegram Group for CAT Preparation.

**Explanation** :

Least the value of (Complete buying/Start buying) for a website, maximum is the leakage in online buying.

Values of (Complete buying/Start buying) are (1200/2500 =) 0.18, (900/2000 =) 0.45, (1300/3000 =) 0.43 and (1600/3500 =) 0.46 for Website B, Website C, Website D and Website E respectively.

So, Website Dsent traffice to www.jay.com with maximum leakage.

Hence, option (c).

Workspace:

**38. IIFT 2015 LRDI | DI - Tables & Graphs**

On which Ad Site is the advertising budget spent most efficiently?

- A.
Website A

- B.
Website B

- C.
Website C

- D.
Website E

Answer: Option A

Join our Telegram Group for CAT Preparation.

**Explanation** :

Efficiency of online display advertising expenditure on

$\mathrm{Website}\mathrm{A}=\frac{2700}{27\%\mathrm{of}557000}=\frac{10}{557}$

Efficiency of online display advertising expenditure on

$\mathrm{Website}\mathrm{B}=\frac{1200}{22\%\mathrm{of}557000}=\frac{5.45}{557}$

Efficiency of online display advertising expenditure on

$\mathrm{Website}\mathrm{C}=\frac{900}{18\%\mathrm{of}557000}=\frac{5}{557}$

Efficiency of online display advertising expenditure on$$

$\mathrm{Website}\mathrm{E}=\frac{1600}{20\%\mathrm{of}557000}=\frac{8}{557}$

Advertising budget was spent most efficiently on Website A.

Hence, option (a).

Workspace:

## Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.