Discussion

Explanation:

a+3b2=9 and a-1b-12=4

a+3b=±3 and a-1b-1=±2

We get following cases:

Case 1(a): a + 3 = 3b and a - 1 = 2b - 2
⇒ a = 3 and b = 2 (Rejected)

Case 1(b): a + 3 = 3b and a - 1 = -2b + 2
⇒ b is not an integer (Rejected)

Case 2(a): a + 3 = -3b and a - 1 = 2b - 2
⇒ b is not an integer (Rejected)

Case 2(b): a + 3 = -3b and a - 1 = -2b + 2
⇒ a = 15 and b = -6
∴ (a/b)2 = (15/-6)2 = 25/4

Hence, option (d).

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