Discussion

Explanation:

As each prime number greater than or equal 3 is of from 6k ± 1, here k is a natural number, p = 6k ± 1.

p2 - 1 = (6k ± 1)2 - 1 = 12k(3k ± 1)

Since k(3k ± 1) is an even number, above number is always divisible by 24 irrespective of value of k.

Hence, option (d).

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