The sum of two integers is 10 and the sum of their reciprocals is 5/12. Then the larger of these integers is
Explanation:
Since the sum of reciprocals is 5/12.
The two numbers must have their LCM as 12 and their sum as given will be 10.
Possible numbers are 4 and 6 only.
Alternately, Let the numbers be a and b.
a + b = 10 ...(1)
1/a + 1/b = 5/12 ...(2)
Solving (1) and (2), we get (a, b) = (4, 6)
Hence, option (c).
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