Discussion

Explanation:

The following diagram represents the given scenario.

​​​​​​​

Let, TR = x

∴ 8 × 18 = x (7 + x)

∴ x2 + 7x – 144 = 0

∴ x = 9 or x = – 16

But x cannot be negative.

Hence, x = 9

A(∆TPS) = 12 × 18 × 16 × sin 60°

= 72√3 sq.units

Hence, option (c).

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