Let a1 , a2 be integers such that a1 - a2 + a3 - a4 + ........ + (-1)n-1 an = n , for n ≥ 1. Then a51 + a52 + ........ + a1023 equals
Explanation:
Given that a1 - a2 + a3 - a4 + ........ + (-1)n-1 an = n
Put n = 1 ⇒ a1 = 1
Put n = 2 ⇒ a1 - a2 = 2 ⇒ a2 = 1 - 2 = -1
Put n = 3 ⇒ a1 - a2 + a3 = 3 ⇒ a3 = 3 – 1 -1 = 1
Hence, the series proceeds as 1, -1, 1, -1, ...
i.e. odd term of the series = +1
& even terms of the series = -1
Then a51 + a52 + ........ + a1023 = 1 + (-1) + .... + 1
⇒ a51 + a52 + ........ + a1023 = 1
Hence, option (b).
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