Discussion

Explanation:

Sum of all 30 integers = 30 × 5 = 150.

Exactly 20 of the 30 integers do not exceed 5 that means the remaining 10 integers are greater than 5.

To keep the average of the first 20 integers as high as possible, we need to keep the average of the remaining 10 integers ,which are above 5, as low as possible. Since we are dealing with integers, the least value that the 10 integers above 5 can take is 6.

So, the sum of the 10 integers = 10 × 6 = 60.

Hence, the sum of the remaining 20 integers = 150 - 60 = 90

∴ The average of the remaining 20 = 90/20 = 4.5

Hence, option (c).

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