A teacher noticed a strange distribution of marks in the exam. There were only three distinct scores: 6, 8 and 20. The mode of the distribution was 8. The sum of the scores of all the students was 504. The number of students in the in most populated category was equal to the sum of the number of students with lowest score and twice the number of students with the highest score. The total number of students in the class was:
Explanation:
Let the number of students scoring 6, 8 and 20 be x, y and z respectively.
So, 6x + 8y + 20z = 504
x + 2z = y
or, 14y + 8z = 504
or, 7y + 4z = 252
By hit and trial we get y = 32 and z = 7
Therefore, x = 18
Therefore, total number of students = 32 + 7 + 18 = 57
Hence, option (e).
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