Discussion

Explanation:

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Applying the concept of similarity,

$\frac{10}{26}=\frac{h}{h+15}$

$\Rightarrow h=9.375 \mathrm{cm}$

Volume of water that overflows can be given as,

$\frac{1}{3}\pi \left[\right({13}^2\times (15+9.375))-(5^2\times 9.375\left)\right]$

$\Rightarrow \frac{1}{3}\pi \left[\right({13}^2\times 24.375)-(5^2\times 9.375\left)\right]$

$\Rightarrow \frac{1}{3}\pi [4119.375-234.375]$

$\Rightarrow 1295\pi {\mathrm{cm}}^3$

Since the radius of the hole is 5 mm i.e. 0.5cm,

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The volume of water flowing in 1 minute,

(0.5² × 1000)π cm³​​​​​​​

Hence, the required time can be given as,

$\frac{1295\pi }{0.5^2\times 1000\pi }=5.18$

Hence, option (d).

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