Discussion

Explanation:

Let A, B be the centre of the two circles with radius 3cm, 8cm respectively.

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AX = 5cm, AP1 = 3cm

Using Pythagoras theorem, P1X = 4cm

Now ∆ A P1X ≈ ∆ B P2X

⇒ A P1/ B P2 = P1X/ P2X

⇒ 3/8 = 4/ P2X

P2X = 10.66

P1 P2 = P1X + P2X = 14.66

Hence, option (c).

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