Discussion

Explanation:

Let QS = x, we get the following figure

​​​​​​​

In any triangle, the sum of any two sides must be greater than the third side. Similarly, the difference between any two sides must be smaller than the third side. Hence,

In ∆QRS,

x + 5 > 17

⇒ x > 12          …(i)

In ∆PQS,

x < 9 + 5

⇒ x < 14         …(ii)

Combining (i) and (ii), we get

12 < x < 14

Hence, option (b).

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