Simran prefers J-type electives and wants to avoid Q-type electives. She noted that the number of only J-type electives is 3. Raj’s preference is G-type electives followed by Q-type electives. However, they want to take as many common electives as possible. What is the maximum number of electives that can be common between them, without compromising their preferences?
Explanation:
Electives common between Simran and Raj are JG type electives. i.e., (z + 4)
Referring to the previous solution, as x = 3, 3z + y = 7
As y ≥ 2, the only possible integer solution to 3z + y = 7 is (z, y) ≡ (1, 4)
Thus, a maximum of 5 electives can be common between Simran and Raj, without compromising their preferences.
Hence, option (c).
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