Discussion

Explanation:

Quality traffic provided by:

$\mathrm{Website} \mathrm{A}=\frac{2800}{120}=23.33$

$\mathrm{Website} \mathrm{B}=\frac{2500}{60}=41.67$

$\mathrm{Website} \mathrm{D}=\frac{3000}{80}=37.5$

$\mathrm{Website} \mathrm{E}=\frac{3500}{40}=87.5$

Thus, Website E has provided maximum quality traffic.

Hence, option (d).

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