Discussion

Explanation:

Let the bus travels at speed ‘V’km/hr  for time ‘T’ hours in the morning.

∴ Distance travelled in the morning = VT km

∴ In the evening, it travels at speed ‘1.5V’km/hr for ‘1.5T’ hours respectively.

∴ Distance travelled in the evening = 1.5V × 1.5T = 2.25VT

∴ Average speed =  Total DistanceTotal Time

=(VT+2.25VT)(T+1.5T)

​​​​​​​=3.25V2.5=1.3V

∴ The average speed of the chartered bus for the entire journey is greater than its average speed in the morning by 30%.

Hence, option (b).

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