Discussion

Explanation:

Consider the image below where A and B are the initial and final position of the man. PQ and LM are the two poles of heights a and b respectively.

​​​​​​​

From ∆PQA, QA = a/Tan60 = a/√3. From ∆ALM, AM = b/Tan45 = b.

From ∆PQB, QB = a/Tan30 = a√3. From ∆BLM, BM = b/Tan60 = b/√3.

∴ [a/√3] + b = a√3 + [b/√3]

Solving we get,

a/b = [(√3) − 1]/2

Hence option (a).

» Your doubt will be displayed only after approval.


Doubts


Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All