Discussion

Explanation:

Total volume of Tunnel = 8 × 16 × 500 = 64000 m3

Radius of the given semicircle = 8 m 

Volume of the semi-circle = (π × 8 × 8)/2 × 500 = 32π × 500 = 16000π m3

∴ Volume of the required cross-section = 64000 - 16000π = 16000(4 − π) m3

Total amount of money needed = 16000(4 − π) × 103 = 16(4 − π) × 106 rupees

Hence, option (c).

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