Discussion

Explanation:

Given,
5 – log101+x + 4log101-xlog1011-x2

⇒  5 – log101+x1/2 + log101-x4/2log101-x2-1/2

⇒  5 = log101+x1/2 - log101-x2 - log101-x21/2

⇒  5 = log101+x1/2(1-x)2×{(1+x)(1-x)}1/2

⇒  5 = log10(1-x)-5/2

⇒ 5 = -5/2 × log10(1 - x)

⇒ -2 = log10(1 - x)

⇒ 1 – x = 10-2 = 1/100

⇒ 100 – 100x = 1

⇒ 100x = 99

Hence, 99.

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