Discussion

Explanation:

Side of the rhombus = ¼ × 40 = 10 cm.

Area of a rhombus = ½ d1d2 = 96 [d1 and d2 are the two diagonals]

⇒ d1d2 = 192

We know, (d1/2)2 + (d2/2)2 = 102

⇒ d12 + d22 = 400

⇒ (d1 + d2)2 - 2d1d2 = 400

⇒ (d1 + d2)2 – 2 × 192 = 400

⇒ (d1 + d2)2 = 784

⇒ d1 + d2 = 28

Hence, the cost of laying electric wore along its two diagonals = 125 × (d1 + d2) = 125 × 28 = Rs. 3,500

Hence, 3500.

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