log2 [3 + log3 {4 + log4 (x - 1)}] - 2 = 0, then 4x equals
Explanation:
Given, log2[3 + log3{4 + log4(x - 1)}] - 2 = 0
⇒ log2[3 + log3{4 + log4(x - 1)}] = 2
⇒ 3 + log3{4 + log4(x - 1)} = 4
⇒ log3{4 + log4(x - 1)} = 1
⇒ 4 + log4(x - 1) = 3
⇒ log4(x - 1) = -1
⇒ x – 1 = ¼
⇒ x = 5/4
⇒ 4x = 5
Hence, 5.
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.