Discussion

Explanation:

Initially the container is full of milk. Let the capacity of container be ‘V’ liters.

When 9 liters are drawn, fraction of quantity drawn = 9V.

Hence, fraction of milk drawn will also be 9V

∴ Fraction of milk remaining will be 1-9V

Only water is added.

⇒ Quantity of milk remaining after first replacement = V1-9V

Similarly, after second replacement quantity of milk remaining = V1-9V2

This is 1625 th  of the total volume.

V1-9V2 = 1625V

⇒ 1 – 9V = 45

⇒ V = 45 liters.

Hence, 45. 

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