Discussion

Explanation:

In ∆ ACD, AC = CD 
⇒ ∠CAD = ∠CDA = 20°

In ∆ ABC
∠ACB = ∠CAD + ∠CDA = (20 + 20)° = 40°   …(Exterior angle theorem)

Also, AC = AB 
⇒ m∠ABC = ∠ACB = 40°

∴ m∠BAD = 180 – 40 – 20 = 120°

Hence, option (d).

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